保留& #xA;在xml编组期间 [英] Retain the 
 during xml marshalling

问题描述

我通过编组xsd来生成xml，我有xsl-fo来生成pdf。我有一个描述字段，必须分解为新行。类似于此线程中的内容使用< xsl：value-of> 在XSL FO中生成的PDF中插入换行符

I am generating the xml by marshalling the xsd and I have xsl-fo to generate the pdf. I have a description field which has to be broken down to new lines.Something similar to what is in this thread Inserting a line break in a PDF generated from XSL FO using <xsl:value-of>

这是我要编组的代码

JAXBContext context = JAXBContext.newInstance(List.class);
            Marshaller m = context.createMarshaller();
            m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
            m.setProperty("com.sun.xml.bind.xmlDeclaration", Boolean.FALSE);
            m.marshal(OrderList, stream);
            StringWriter sw = new StringWriter();
            m.marshal(OrderList, sw);
            String val = sw.toString();
            System.out.println(val);

当我编队时，生成的xml不会保留& #xA; 而是添加& amp; #xA; ，结果就像这样
< description> ;维修CAB DOOR& amp; #xA; REPAIR& amp; #xA;< / description> 。如果我在xml中没有& #xA ，我就无法在我的pdf中创建换行符。

When I marshall, generated xml doesn't retain 
 instead it adds 
 and the result is something like this <description>REPAIR CAB DOOR&amp;#xA;REPAIR &amp;#xA;</description>. If I don't have &#xA in the xml I can't create a line break in my pdf.

推荐答案

好的，我猜这里（虽然有些受过教育）。无论您输入的是< description> 元素，它都不应包含& #xA ，而只是'\ n''。即，而不是：

Ok, I' guessing here (albeit somewhat educated). Whatever your input is to the generation of the <description> element, it should not contain &#xA, but rather just '\n'. I.e., instead of:

"This is a List:
List item 1
List item 2
List item 3
List item 4"

它应该是

"This is a List:\nList item 1\nList item 2\nList item 3\nList item 4"

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