将blob的所有快照检索到单个文件中 [英] Retrieving all snapshots of a blob into a single file
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问题描述
大家好，
我正在尝试将blob的所有快照（包括blob当前数据）检索到单个文件。我尝试了以下程序，但它无法成功并将数据存入文件。在检索数据时，我在函数
中指定了快照详细信息，请调用get_blob_to_text：
      ＃将blob及其快照中的内容转换为单个文件
      tstblob = self._get_resource_reference（" cpyblob"）
      self.service.put_block（container_name，tstblob，b" Hello"，'1'）
      block_list = [BlobBlock（id =" 1"）]
      self.service.put_block_list（container_name，tstblob，block_list）
      self.service.snapshot_blob（container_name，tstblob）       #Snapshot1
   
      self.service.put_block（container_name，tstblob，b" World"，'1'）
      block_list = [BlobBlock（id =" 1"）]
      self.service.put_block_list（container_name，tstblob，block_list）
      self.service.snapshot_blob（container_name，tstblob）       #Snapshot2
      self.service.put_block（container_name，tstblob，b"我很好"，"1"）
      block_list = [BlobBlock（id =" 1"）]
      self.service.put_block_list（container_name，tstblob，block_list）
      list_blobs = self.service.list_blobs（container_name，prefix =" cpyblob"，include = Include.SNAPSHOTS）
      fp = open（'Out.txt'，'a'）
     对于list_blobs中的blob：
         打印（blob.name）     
         打印（blob.snapshot） 
          b = self.service.get_blob_to_text（container_name，blob.name，blob.snapshot）
         打印（b.content）
          fp.write（b.content）
      fp.close（）
      fp = open（'Out.txt'，'r'）
      buf = fp.read（）
      print（buf）
         
谢谢，
skri
解决方案
对延迟道歉！ / p>
尝试下面提到的代码，如果您在此查询中需要更多帮助，请告知我们。
＃ - * - 编码：utf-8 - * -
"""
创建于5月8日星期三11:41:04 2019
@author：moverm
"""
导入os，uuid，sys
来自azure.storage.blob import BlockBlobService，PublicAccess
def run_sample（）：
try：
＃创建用于为存储帐户调用Blob服务的BlockBlockService
block_blob_service = BlockBlobService（account_name ='#####'，account_key ='####'）
＃创建一个名为'quickstartblobs'的容器。
container_name ='quickstartblob'
block_blob_service.create_container（container_name）
＃设置权限以使blob是公共的。
block_blob_service.set_container_acl（container_name，public_access = PublicAccess.Container）
＃在Documents中创建一个文件来测试上传和下载。
local_path = os.path.expanduser（"〜/ Documents"）
local_file_name =" QuickStart1.txt"
full_path_to_file = os.path.join（local_path，local_file_name）
＃将文本写入文件。
file = open（full_path_to_file，'w'）
file.write（" Hello，World！"）
file.close（）
print（ " Temp file =" + full_path_to_file）
print（" \ nnpup to Blob storage as blob" + local_file_name）
＃上传创建的文件，使用local_file_name作为blob名称
block_blob_service.create_blob_from_path（container_name，local_file_name，full_path_to_file）
＃列出容器中的blob
print（容器中的"\ nList blobs"）
generator = block_blob_service.list_blobs（container_name）
for blob in generator：
print（" \t Blob name：" + blob.name）
＃下载blob （S）。
＃将'_DOWNLOADED'添加为'.txt'的前缀，这样您就可以在Documents中看到这两个文件。
full_path_to_file2 = os.path.join（local_path，str.replace（local_file_name，'。txt'，'_ DOWNLOADED.txt'））
print（" \\\
Downloading blob to" + full_path_to_file2）
＃block_blob_service.get_blob_to_path（container_name，local_file_name，full_path_to_file2）
block_blob_service.put_block（container_name，local_file_name，b" World"，'1'）
block_blob_service.snapshot_blob（container_name， local_file_name）
print（" \ nnnding first snapshot"）
block_blob_service.put_block（container_name，local_file_name，b" I am Feeling Lucky"，'2'）
block_blob_service.snapshot_blob（container_name ，local_file_name）
print（" \ nnAdding first snapshot"）
#list_blobs = block_blob_service.list_blobs（container_name，prefix =" QuickStart1"，include ='snapshots'）
#fp = open（'Out.txt ，'a'）block_blob_service.list_blobs中blob的
（container_name，prefix =" QuickStart1"，include ='snapshots'）：
print（blob.name，blob.snapshot）
block_blob_service.get_blob_to_path （container_name，blob.name，full_path_to_file2，open_mode ='ab'，snapshot = blob.snapshot，start_range = 0）
除了异常为e：
print（e）
＃主要方法。
如果__name__ =='__ main__'：
run_sample（）
您也可以参考
SO 主题其中有类似的问题
请告知我们上述内容是否有帮助，或者您需要在此问题上获得进一步的帮助。
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Hi All,
I am trying to retrieve all snapshots of a blob including the blob current data to a single file. I tried the following program but it couldn't succeeded and get the data to a file. While retrieving the data i am specifying the snapshot detail in the function call get_blob_to_text:
# To get contents from blob and its snapshots to a single file
tstblob = self._get_resource_reference("cpyblob")
self.service.put_block(container_name, tstblob, b"Hello", '1')
block_list = [BlobBlock(id = "1")]
self.service.put_block_list(container_name, tstblob, block_list)
self.service.snapshot_blob(container_name, tstblob) # Snapshot1
self.service.put_block(container_name, tstblob, b"World", '1')
block_list = [BlobBlock(id = "1")]
self.service.put_block_list(container_name, tstblob, block_list)
self.service.snapshot_blob(container_name, tstblob) # Snapshot2
self.service.put_block(container_name, tstblob, b"I am fine", '1')
block_list = [BlobBlock(id = "1")]
self.service.put_block_list(container_name, tstblob, block_list)
list_blobs = self.service.list_blobs(container_name, prefix="cpyblob", include=Include.SNAPSHOTS)
fp = open('Out.txt', 'a')
for blob in list_blobs:
print(blob.name)
print(blob.snapshot)
b = self.service.get_blob_to_text(container_name, blob.name, blob.snapshot)
print(b.content)
fp.write(b.content)
fp.close()
fp = open('Out.txt', 'r')
buf = fp.read()
print(buf)
Thanks,
skri
解决方案Apologies for the delay!
Try the code mentioned below and let me know if you need any more assistance on this query
# -*- coding: utf-8 -*- """ Created on Wed May 8 11:41:04 2019 @author: moverm """ import os, uuid, sys from azure.storage.blob import BlockBlobService, PublicAccess def run_sample(): try: # Create the BlockBlockService that is used to call the Blob service for the storage account block_blob_service = BlockBlobService(account_name='#####', account_key='####') # Create a container called 'quickstartblobs'. container_name ='quickstartblob' block_blob_service.create_container(container_name) # Set the permission so the blobs are public. block_blob_service.set_container_acl(container_name, public_access=PublicAccess.Container) # Create a file in Documents to test the upload and download. local_path=os.path.expanduser("~/Documents") local_file_name ="QuickStart1.txt" full_path_to_file =os.path.join(local_path, local_file_name) # Write text to the file. file = open(full_path_to_file, 'w') file.write("Hello, World!") file.close() print("Temp file = " + full_path_to_file) print("\nUploading to Blob storage as blob" + local_file_name) # Upload the created file, use local_file_name for the blob name block_blob_service.create_blob_from_path(container_name, local_file_name, full_path_to_file) # List the blobs in the container print("\nList blobs in the container") generator = block_blob_service.list_blobs(container_name) for blob in generator: print("\t Blob name: " + blob.name) # Download the blob(s). # Add '_DOWNLOADED' as prefix to '.txt' so you can see both files in Documents. full_path_to_file2 = os.path.join(local_path, str.replace(local_file_name ,'.txt', '_DOWNLOADED.txt')) print("\nDownloading blob to " + full_path_to_file2) #block_blob_service.get_blob_to_path(container_name, local_file_name, full_path_to_file2) block_blob_service.put_block(container_name, local_file_name, b"World", '1') block_blob_service.snapshot_blob(container_name,local_file_name) print("\nAdding first snapshot") block_blob_service.put_block(container_name, local_file_name, b"I am Feeling Lucky", '2') block_blob_service.snapshot_blob(container_name,local_file_name) print("\nAdding first snapshot") #list_blobs = block_blob_service.list_blobs(container_name, prefix="QuickStart1", include='snapshots') #fp = open('Out.txt', 'a') for blob in block_blob_service.list_blobs(container_name,prefix="QuickStart1", include='snapshots'): print (blob.name, blob.snapshot) block_blob_service.get_blob_to_path(container_name,blob.name, full_path_to_file2,open_mode='ab',snapshot=blob.snapshot,start_range=0) except Exception as e: print(e) # Main method. if __name__ == '__main__': run_sample()You may also refer to SO thread which has the similar issue
Kindly let us know if the above helps or you need further assistance on this issue.
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