为什么不能成功编译？ [英] Why won't it compile successfully?

问题描述

#include <iostream>
#include <string>
using namespace std;

class Sales_item
{
private:
    string m_strName;
public:
    Sales_item(string name):m_strName(name){};
    void Display(ostream& os) {os << m_strName}; /*This line is wrong.*/
};

当我尝试编译上面的代码时，它会显示错误C2143：语法错误：缺少';''之前'}' 。我需要解释为什么它不会编译。在此先感谢。

When I try to compile the code above, it says "error C2143: syntax error : missing ';' before '}'". I need an explanation why it won't compile. Thanks in advance.

推荐答案

我认为你的问题渗透了足够的时间，所以我会跳进去做一些小的贡献。你没有在正确的地方使用分号。



你的代码：

Your question has percolated for enough time I think, so I'll jump in and make a small contribution. You don't have your semicolons in the right place.

Your code:

Sales_item(string name):m_strName(name){};
void Display(ostream& os) {os << m_strName};

应该是：

should be:

Sales_item(string name):m_strName(name){}  // (no semicolon)
void Display(ostream& os) {os << m_strName;} // (semicolon before brace not after)

在结束括号之后使用分号在语法上不正确，但在类定义中它们是多余的...

It is not syntactically incorrect to have semicolons after the closing braces, but they are superfluous in a class definition...

C / C ++需要分号作为结束命令指示器。您的 Display（）函数包含必须终止的命令。所以必须是：

The semicolon is required with C/C++ as end of command indicator. Your Display() function contains a command that must be terminated. So it must be:

void Display(ostream& os) {os << m_strName;}

此处不需要分号，因为定义了 Display（）函数（包含实现）并且未声明。

The semicolon at the end is not required here, because the Display() function is defined (containing the implementation) and not declared.

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