sql server 2008中表中的子节点 [英] sub node in a table in sql server 2008
本文介绍了sql server 2008中表中的子节点的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
2
down vote
favorite
I have structure like this:
<Unit>
<SubUnit1>
<SubSubUnit1/>
<SubSubUnit2/>
...
<SubSubUnitN/>
</SubUnit1/>
<SubUnit2>
<SubSubUnit1/>
<SubSubUnit2/>
...
<SubSubUnitN/>
</SubUnit2/>
...
<SubUnitN>
<SubSubUnit1/>
<SubSubUnit2/>
...
<SubSubUnitN/>
</SubUnitN/>
</Unit>
This structure has 3 levels: main Unit, SubUnits and SubSubUnits.
I want to select all children by UnitId.
If I search by Unit, I have to get all tree.
If I search by SubUnit1, I have to get SubUnit1 and all children of SubUnit1.
If I search SubSubUnit2, I have to get itself.
推荐答案
考虑使用递归CTE。它将返回一个包含所有子项的行的表。详情请见:http://stackoverflow.com/questions/14274942/sql-server-cte-and-recursion-example
Consider using recursive CTE for that. It will return a table with rows containing all children. See here for details: http://stackoverflow.com/questions/14274942/sql-server-cte-and-recursion-example
这篇关于sql server 2008中表中的子节点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文