发布一个JSON到一个RESTful Web服务,得到了HTTP 200(OK),但它只是返回我原来的JSON对象 [英] Posting a Json to a Restful webservice, getting the HTTP 200 (OK) but it returns just my original Json object

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问题描述

所以我张贴此JSON这个RESTful Web服务和职位是成功的(HTTP code:200),但是我回来作为响应原始JSON对象的发布。这是一个普通的行为呢?

SO I post this json to this restful web service and the post is successful (http code:200) however I get back as a response the original Json object that posted. Is this a regular behavior ?

InputStream in = null;
    int resCode;
    String text;

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);




     // POST request to <service>/SaveVehicle
        HttpPost request = new HttpPost("http://origin.staging.scion.com/PE/service/rest/getit");
        //request.setHeader("Accept", "application/json");
        request.setHeader("Content-type", "application/json");
        request.setHeader("user-agent", "Yoda");
        try {
        // Build JSON string
        JSONStringer vehicle = new JSONStringer()
            .object()
                .key("getItInputTO")
                    .object()
                        .key("zipCode").value("90505")
                        .key("financingOption").value("B")
                        .key("make").value("Scion")
                        .key("baseAmountFinanced").value("12000")
                        .key("modelYear").value("2010")
                        .key("trimCode").value("6221")
                        .key("totalMSRP").value("15000")
                        .key("aprRate").value("")
                    .endObject()
                .endObject();

        StringEntity entity = new StringEntity(vehicle.toString());


        request.setEntity(entity);

        // Send request to WCF service
        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpResponse response = httpClient.execute(request); 
        resCode = response.getStatusLine().getStatusCode();
        Toast.makeText(getApplicationContext(),response.getStatusLine().getStatusCode()+"", Toast.LENGTH_LONG).show();   

        if (resCode == 200) {

            Toast.makeText(getApplicationContext(),response.getStatusLine().getStatusCode()+"", Toast.LENGTH_LONG).show();   
            BufferedReader in = 
                new BufferedReader(new InputStreamReader(entity.getContent()));
            String line="";
            StringBuffer returnFromServer = new StringBuffer();

            while ((line=in.readLine())!=null) 
            {
                returnFromServer.append(line);
            }
            //Toast what we got from server
            Toast.makeText(getApplicationContext(),returnFromServer.toString(), Toast.LENGTH_LONG).show();   


            if (entity != null) 
            {
                entity.consumeContent();
            }

        }  
        }catch (Exception e) {
            // TODO: handle exception
        }  

任何想法都超过欢迎。

any Ideas are more than welcomed.

推荐答案

你所读的的BufferedReader 是原始请求的实体:

What you are reading in your BufferedReader is the entity of the original request:

BufferedReader in = new BufferedReader(new InputStreamReader(entity.getContent()));

以上行是罪犯。你想从响应读取实体,像这样的:

The above line is the offender. You want to read in the entity from the response, like this:

BufferedReader in = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

这篇关于发布一个JSON到一个RESTful Web服务,得到了HTTP 200(OK),但它只是返回我原来的JSON对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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