如何在Record类中获取Field类的属性 [英] How to get the property of Field class in Record class

问题描述

public class Record
    {
        public List<field> Field_list = new List<field>();
        public Record()
        {
            Field h = new Field();
            h.StructureField_Identifier = "";
            Field.Add(h);
            
        }
    }

    public class Field
    {
               
        public string StructureField_Identifier { get; set; }
     }

//我在公共字符串StructureField_Identifier获取值。我必须在Field_list列表中获取该值。所以我使用的是Constructor Record（）和Field实例。但我无法得到它。如何在Record类中获取Field类的属性

//I am getting the value at public string StructureField_Identifier. I have to get that value in the list "Field_list". So I am using Constructor Record() and Field instance. But I am not able to get it. How to get the property of Field class in Record class

推荐答案

public class Record
{
    public List<Field> Field_list = new List<Field>();
    public Record()
    {
        //insted of this
        Field h = new Field();
        h.StructureField_Identifier = "";
        //replace this line
        Field_list.Add(new Field { StructureField_Identifier = "" });

    }
}

public class Field
{

    public string StructureField_Identifier { get; set; }
}

in

in

Field_list

你可以得到一个属性值。

you can get a value of property.

更改构造函数（编译）：

Change your constructor (so it compiles):

public Record()
{
    Field h = new Field();
    h.StructureField_Identifier = "";
    Field_list.Add(h);

}

然后尝试：

Then try:

Record r = new Record();
Field f = r.Field_list[0];
String s = f.StructureField_Identifier;

感谢您给出答案......但我仍然无法得到它。你可以为此发布一些其他选项......

Thanks for giving answers... Still I am not able to get it. Can you please post some other options for this...

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