如何将值从函数传递给属性 [英] How to pass the value from function to property

问题描述

  public   class 字段
 {
 
 
  public   string  StructureField_Identifier {获得;  set ; } 
  public   string  func_in_field（ string  a）
 {
 Field n =  new  Field（）; 
 n.StructureField_Identifier = a; 
  return  n; 
} 
} 

//要将函数func_in_field中的字符串a传递给公共字符串StructureField_Identifier，我使用的是n.StructureField_Identifier 。但我无法通过。如何将值从函数传递给属性。

解决方案

除非我不理解你，否则它应该是：

  public   class 字段
 { 
  public   string  StructureField_Identifier { get ;  set ; } 
 
  public   string  func_in_field（ string  a）
 {
 StructureField_Identifier = a;  //  在此实例中为属性分配。 
 返回 a;  //   ????  
} 
} 
 

你好，



Ron Sir的帖子是正确的



首先，

  public   class 字段
 {
 
 
  public   string  StructureField_Identifier { get ;  set ; } 
  public   string  func_in_field（ string  a）
 {
 Field n =  new  Field（）; 
 n.StructureField_Identifier = a; 
  return  n; 
} 
} 

您的方法func_in_field的返回类型是一个字符串和您拥有的类型用来返回的是Field



所以这段代码不会编译。



它给出的错误是：

Quote：

无法将类型字段转换为字符串

要编译它，请执行以下操作：

  public   string  func_in_field（ string  a）
 {
 Field n =  new  Field（）; 
 n.StructureField_Identifier = a; 
  return  n.StructureField_Identifier; 
} 

现在确认在
$ b $添加断点b

引用：

返回n.StructureField_Identifier;

将鼠标悬停在

引用：

n.StructureField_Identifier = a;

你会看到价值被分配。



你的问题听起来像是一个运行时异常（这意味着在运行时没有分配值），但是正好与编译时异常相反。



所以你不能继续，你需要解决它。



谢谢，

- Rahul

使用

  this  .StructureField_Identifier = a; 

而不是

  n.StructureField_Identifier =一个;  

public class Field
   {

     
             public string StructureField_Identifier { get; set; }
             public string func_in_field(string a)
       {
           Field n = new Field();
           n.StructureField_Identifier = a;
           return n;
       }
  }

// To pass the string "a" from function "func_in_field" to public string StructureField_Identifier, I am using n.StructureField_Identifier. But I am not able pass. How to pass the value from function to property.

解决方案

Unless I'm not understanding you right, it should be:

public class Field
{
    public string StructureField_Identifier { get; set; }

    public string func_in_field(string a)
    {
        StructureField_Identifier = a;   //Assigns a to the property in this instance.
        return a;   //????
    }
}

Hello,

Ron Sir's post is correct

Firstly,

public class Field
   {


             public string StructureField_Identifier { get; set; }
             public string func_in_field(string a)
       {
           Field n = new Field();
           n.StructureField_Identifier = a;
           return n;
       }
  }

The return type of your method "func_in_field" is a string and the type you have used to return is of "Field"

So this code wont compile.

The error it gives is :

Quote:

cant convert type Field to type string

To make it compile do this :

public string func_in_field(string a)
      {
          Field n = new Field();
          n.StructureField_Identifier = a;
          return n.StructureField_Identifier;
      }

Now to confirm add a a breakpoint at

Quote:

return n.StructureField_Identifier;

Hover your mouse to

Quote:

n.StructureField_Identifier = a;

And you will see that the value is assigned.

Your question is sounding like it is a run time exception(Which means value is not getting assigned at run time), but it is exactly opposite you are getting a compile time exception.

So you cant go ahead, you will need to solve it.

Thanks,
- Rahul

use

this.StructureField_Identifier = a;

instead of

n.StructureField_Identifier = a;

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