如何在C＃asp.net中的Gridview单元格中调用FileUpload？ [英] How to call FileUpload in Gridview cell in C# asp.net?

问题描述

您好，



我想使用编辑更新图像，使用C＃asp.net gridview更新，

所以，如何调用C＃asp.net中Gridview单元格中的FileUpload？



我把GridUpload放在Gridview Cell中，但是当我们使用文件上传调用图像时，它的空白图像进入变量，我将此代码用于更新映像： -

 FileUpload Image1 =（FileUpload）GVStartCampaignDetails.Rows [e.RowIndex] .FindControl（  Image1）;  //  图像在图像字段中填空。 
  string  filename = System.IO.Path .GetFileName（Image1.FileName）; 
会话[  UpdateImage] = filename; 
 Image1.SaveAs（Server.MapPath（  Templates /）+ filename +  。jpg）; 
 SqlConnection con =  new  SqlConnection（connectionString）; 
 con.Open（）; 
 SqlCommand cmd =  new  SqlCommand（  procUpdateImage ，con）; 
 cmd.CommandType = CommandType.StoredProcedure; 
 cmd.Parameters.Add（  @ EmailId，SqlDbType.NVarChar）.Value =电子邮件ID; 
 cmd.Parameters.Add（  @ ImagePath，SqlDbType.NVarChar）.Value =会话[  UpdateImage]。ToString（）; 
 cmd.ExecuteNonQuery（）; 
 con.close（）; 

请帮助我。



先谢谢。

解决方案

查看此内容。



在asp.net gridview的每一行上传文件 [ ^ ]

当它处于编辑模式时如何在gridview中上传文件。 [ ^ ]

请参阅以下链接以获取图像并在网格中显示： -

http://www.c-sharpcorner.com/UploadFile/0c1bb2/uploading-and-displaying-images-from-database-using-Asp-Net/ [ ^ ]

http://www.aspdotnet-suresh.com/2011/01/how-to-insert-images-into-database-and.html [ ^ ]

http://aspsnippets.com/Articles/Upload-images-to-folder-and-display-uploaded-images-in-ASPNet-GridView-using-C-and-VBNet.aspx [ ^ ]

In aspx

 <％@    < span class =code-leadattribute> Page    语言  =  C＃    AutoEventWireup   =  true    CodeFile   =  FileUploadInsideGridView.aspx.cs   继承  =  FileUploadInsideGridView   ％>  
 
 
 <  ！DOCTYPE     html     PUBLIC     -  // W3C // DTD     XHTML     1.0     Transitional // EN   http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd < span class =code-keyword>>  
 
 
 <   html     xmlns   =  http://www.w3.org/1999/xhtml > ;  
 <   head     runat   =  server >  
 <   title  >  <   / title  >  
 <   / head  >  
 <   body  >  
 <  表单    id   =  form1    runat   =  server >  
 <   div  >  
 <   asp：GridView     ID   =  GridView1    runat   =  server < span class =code-attribute>   AutoGenerateColumns   =  False  
   
                           DataKeyNames   =  PersonID    DataSourceID   =  SqlDataSource1  
   
                           onrowcommand   =  GridView1_RowCommand   >  
 <  列 >  
 <   asp：BoundField     DataField   =  FirstName    HeaderText   =  FirstName  
   
                                           SortExpression   =  FirstName    /  >  
 <   asp：BoundField     DataField   =  LastName    HeaderText   =  LastName  
   
  < span class =code-attribute>                                         SortExpression   =  LastName < span class =code-attribute>   /  >  
 <   asp：TemplateField     HeaderText   = 上传 >  
 <   ItemTemplate  >  
 < ;   asp：FileUpload     ID   =  FileUpload1    runat   =  server    EnableViewState   =  true     /  >  
  <   asp：按钮    ID   =  saveBtn    runat   =  server  
   
                          < span class =code-attribute>                                 CommandArgument   =  <％ #Container.DataItemIndex ％>     CommandName  < span class =code-keyword> =  save  
  < span class =code-attribute> 
                                < span class =code-attribute>                          文本  = 确定 < span class =code-keyword> /  >  
 <   / ItemTemplate  >  
 <   / asp：TemplateField  >  
  <％ -    < asp：ButtonField ButtonType =ButtonCommandName =saveText =Save/>    - ％>   
 <   / Columns  >  
 <   / asp：GridView  >  
 <   asp：SqlDataSource  < span class =code-attribute>   ID   =  SqlDataSource1    runat   =   server  
   
        < span class =code-attribute>                   ConnectionString   =  <％ 

Hello,

I want to update image using Edit,Update using C# asp.net gridview,
So, How to call FileUpload in Gridview cell in C# asp.net?

I placed FileUpload in Gridview Cell but when we call image using file upload, it,s blank image going in to the variable, I am using this code for Update Image:-

FileUpload Image1 = (FileUpload)GVStartCampaignDetails.Rows[e.RowIndex].FindControl("Image1");// Image it's filling blank in Image Field.
        string filename = System.IO.Path.GetFileName(Image1.FileName);
        Session["UpdateImage"] = filename;
Image1.SaveAs(Server.MapPath("Templates/") + filename + ".jpg");
                    SqlConnection con = new SqlConnection(connectionString);
                    con.Open();
                    SqlCommand cmd = new SqlCommand("procUpdateImage", con);
                    cmd.CommandType = CommandType.StoredProcedure;
                    cmd.Parameters.Add("@EmailId", SqlDbType.NVarChar).Value = EmailId;
cmd.Parameters.Add("@ImagePath", SqlDbType.NVarChar).Value = Session["UpdateImage"].ToString();
cmd.ExecuteNonQuery();
con.close();

Please Help me.

Thanks in Advance.

解决方案

Check this.

Upload file in each row of asp.net gridview[^]
How to upload a file in gridview when it is in EDIT mode.[^]

Refer below links for retriving images and show in grid:-
http://www.c-sharpcorner.com/UploadFile/0c1bb2/uploading-and-displaying-images-from-database-using-Asp-Net/[^]
http://www.aspdotnet-suresh.com/2011/01/how-to-insert-images-into-database-and.html[^]
http://aspsnippets.com/Articles/Upload-images-to-folder-and-display-uploaded-images-in-ASPNet-GridView-using-C-and-VBNet.aspx[^]

In aspx

<%@ Page Language="C#" AutoEventWireup="true" CodeFile="FileUploadInsideGridView.aspx.cs" Inherits="FileUploadInsideGridView" %>


<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">


<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title></title>
</head>
<body>
    <form id="form1" runat="server">
    <div>
        <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"

            DataKeyNames="PersonID" DataSourceID="SqlDataSource1"

            onrowcommand="GridView1_RowCommand" >
            <Columns>
                <asp:BoundField DataField="FirstName" HeaderText="FirstName"

                    SortExpression="FirstName" />
                <asp:BoundField DataField="LastName" HeaderText="LastName"

                    SortExpression="LastName" />
                <asp:TemplateField HeaderText="Upload">
                    <ItemTemplate>
                        <asp:FileUpload ID="FileUpload1" runat="server" EnableViewState="true" />
                        <asp:Button ID="saveBtn" runat="server"

                            CommandArgument="<%# Container.DataItemIndex%>" CommandName="save"

                            Text="OK"/>
                    </ItemTemplate>
                </asp:TemplateField>
                <%--<asp:ButtonField ButtonType="Button" CommandName="save" Text="Save"/>--%>
            </Columns>
        </asp:GridView>
        <asp:SqlDataSource ID="SqlDataSource1" runat="server"

            ConnectionString="<%

这篇关于如何在C＃asp.net中的Gridview单元格中调用FileUpload？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！