可以使用函数指针调用静态方法吗？如果是这样我们怎么称呼它？ [英] Can a Static method be called using a function pointer? if so how can we call it?

问题描述

使用函数指针调用静态方法

Calling a static method using a function pointer

推荐答案

这与使用任何方法的指针的方式相同，例如：

It is the same way you would use a pointer for any method, for example:

class CTest
{
    //
public:
    static int staticProc();
    static int staticTwo(int a, int b, char* psz);
};

// then in your main code, something like

    int (*pfun)() = CTest::staticProc; // pfun is the pointer to the static function
    int foo = pfun();  // call the function through the pointer

有时使用 typedef 会很有帮助：

Sometimes it can be helpful to use a typedef like:

typedef int		(*TFUN)(int a, int b, char* pc);
TFUN pfun = (TFUN)CTest::staticTwo;
int foo = pfun(1, 2, "foo");

静态方法与普通C函数完全一样，它们只是在命名空间内，如果函数可以某种方式获取指向类实例的指针，它们可以访问类的私有/受保护成员。另一个特点是你也可以使用静态方法的可见性，如果你把它放到保护或私有，那么它就不能从任何地方调用。

A static method works exactly like normal C functions, they are just inside a namespace and they have access to private/protected members of the class if the function can somehow get a pointer to the instance of the class. Another feature is that you can also play with the visibility of the static method, if you put it to protected or private then it can not be called from anywhere.

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