重新升级XSLT For -each循环 [英] Regrading XSLT For -each loop

问题描述

1。我如何从XSLT中的单词中获取1个字母。



例如：我有xml像

1. How do i fetch 1 by 1 letter from word in XSLT.

EXample: i have xml like

  <cricket>
  <player>
    <name>sachin Tendulkar </name>
  </player>
   <player>
    <name>Virat Kohili </name>
  </player>
</cricket>

i希望显示为

i want to display like

<tr>
  <td> s </td>
  <td> a </td>
  <td> c </td>
  <td> h </td>
  <td> i </td>
  <td> n </td>
  <td>   </td>
  <td> T </td>
  <td> e </td>
  <td> n </td>
  <td> d </td>
  <td> u </td>
  <td> l </td>
  <td> k </td>
  <td> a </td>
  <td> r </td>
</tr>

与virat kohili名称相同。我想要中的每个单词< table> ;< tbody>< tr>< td> 标记，用于混淆单词或在前端交换单词的位置....

Plz立即回复...

谢谢。

same for virat kohili name .i want to every word in <table><tbody><tr><td> tag,for jumble the word or exchange the position of word in front end ....
Plz reply soon...
thanks.

推荐答案

1.获取XML文件的实例

2.use xmlreader获取xml成员

1.Get instance of your XML file
2.use xmlreader to get xml members

string xml = "  <span><myVal>Sachin</myVal><myVal>Virat</myVal><myVal></span>";
XmlReader xr = XmlReader.Create(new StringReader(xml));
var xmlMembers = from members in XElement.Load(xr).Elements() select members;

foreach (XElement x in xmlMembers)
{
    // nodeValue will has Sachin in it
    var nodeValue = x.Value;
}

这个节点值你可以根据你的需要操纵furthur和Jumble这个词并在UI中显示它

with this nodevalue you can manipulate furthur as per your need and Jumble the word and show it int UI

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:m="http://www.w3.org/1998/Math/MathML">
	xmlns:qti="http://www.imsglobal.org/xsd/imsqti_v2p1">
  <xsl:output indent="yes" />
  <xsl:template match="/">
    <xsl:apply-templates />
  </xsl:template>
  <xsl:template match="name" name="Test">
          <xsl:param name="text" select="node()" />
          <xsl:if test="

text！='' >
< xsl：变量 名称 = 字母 选择 = substring（

text != ''"> <xsl:variable name="letter" select="substring(

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