DateDiff问题（VB .net 4.0） [英] Issue with DateDiff (VB .net 4.0)

问题描述

嗨!!，

对于我的一个项目，我在计时器中使用DateDiff功能，如下所述： -



NoOfValues = DateDiff（DateInterval.Second，StartTime，EndTime）



StartTime，EndTime&执行周期的NoOfValues如下所述

Hi!!,
For one of my project i'm using DateDiff function in a timer as mentioned below:-

NoOfValues = DateDiff(DateInterval.Second, StartTime, EndTime)

the values of StartTime, EndTime & NoOfValues for a cycle of execution are as mentioned below

Start Time= 11/18/2013 4:28:46 PM   End Time= 11/18/2013 4:29:37 PM
NoOfValues= 51

Start Time= 11/18/2013 4:29:38 PM   End Time= 11/18/2013 4:29:49 PM
NoOfValues= 10

Start Time= 11/18/2013 4:29:50 PM   End Time= 11/18/2013 4:30:00 PM
NoOfValues= 10

我无法理解

I'm not able to understand how the difference of

[11/18/2013 4:29:38 PM & 11/18/2013 4:29:49 PM] =10 

Plz指导我是否我已正确使用DateDiff函数。

Plz guide me whether i've used DateDiff function correctly.

推荐答案

您可以使用TimeSpan处理DateTime值的计算：

You could use a TimeSpan to handle calculations on your DateTime values:

Dim myDate1 As DateTime = new DateTime(2013, 11, 18, 4, 29, 38);
Dim myDate2 As DateTime = new DateTime(2013, 11, 18, 4, 29, 49);
TimeSpan ts = myDate2 - myDate1;
long elapsedInMilliseconds = ts.Elapsed;
float valueInSeconds = (float)elapsedInMilliseconds / 1000f;
int value = Math.Floor(valueInSeconds);

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