在代码中找到错误.... [英] find error... in the code

问题描述

  #include   <   iostream.h  >  
  使用 std :: cout; 
 使用 std :: cin; 
  int  main（）; 
 {
  int  netsalary; 
  int  basicsalary; 
  int 奖金; 
  int  tax; 
 cout<<  请输入基本工资和奖金; 
 cin>> basicsalary; 
 cin>>奖金; 
  if （basicsalary< =  1000 ）
 tax = basicsalary * 10/100 ; 
  else  tax = basicsalary * 20/100; 
 netsalary = basicsalary + bonus-tax; 
 cout<< netsalary; 
  return   0 ; 
} 

（enhzflep：已添加代码标签）

解决方案

< blockquote>你的编译器没有找到错误吗？



有几个...



例如

  int  main（）; 

没时间对他们发表评论......



看看这本并开始阅读一本关于C ++的书。

  #include    <   iostream  >  
  
 < span class =code-keyword>使用 命名空间标准; 
 
  int  main（）
 {
  int  netsalary; 
  int  basicsalary; 
  int 奖金; 
  int  tax; 
 cout<<  请输入基本工资：; 
 cin>>基础工资; 
 cout<<  和红利：; 
 cin>>奖金; 
 
  if （basicsalary< =  1000 ）
 tax = basicsalary * 10/100; 
 其他 
 tax = basicsalary * 20/100; 
 
 netsalary = basicsalary + bonus-tax; 
 cout<< netsalary; 
 
  return   0 ; 
} 

你真的想用int结果计算吗？

我的解决方案仅基于代码的静态分析

1.由于分割导致的整数数据类型导致截断

2.第二个输入（甚至第一个）值可能已损坏，因为用户可能不知道如何区分两个输入（空格，逗号等）

3.是否接受负值？

#include <iostream.h>
using std::cout;
using std::cin;
int main();
{
    int netsalary;
    int basicsalary;
    int bonus;
    int tax;
    cout<<"please enter the basic salary and the bonus";
    cin>>basicsalary;
    cin>>bonus;
    if ( basicsalary<=1000 )
    tax=basicsalary*10/100;
    else tax=basicsalary*20/100;
    netsalary=basicsalary+bonus-tax;
    cout<<netsalary;
    return 0;
}

(enhzflep: code-tags added)

解决方案

Does your Compiler not find the errors ?

There are several of them ...

For example

int main();

No time to comment them all ...

Take a look at this and start reading a book about C++.

#include <iostream>

using namespace std;

int main()
{
int netsalary;
int basicsalary;
int bonus;
int tax;
cout << "please enter the basic salary: ";
cin >> basicsalary;
cout << " and the bonus: ";
cin >> bonus;

if( basicsalary<=1000 )
   tax=basicsalary*10/100;
else
   tax=basicsalary*20/100;

netsalary=basicsalary+bonus-tax;
cout<<netsalary;

return 0;
}

Do you really want calculation with int result ?

My solution is based on only the static analyis of your code
1. Intger data types as a result of division oeration result in truncation
2. 2nd input ( or even 1st) values may be corrupted as user may not not know how to differentiate the two inputs ( space,comma etc)
3. Is Negative values accepted?

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