如何删除从Android的联系人列表中的重复接触 [英] how to remove duplicate contact from contact list in android
本文介绍了如何删除从Android的联系人列表中的重复接触的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
请看看： -
公共静态的ArrayList＆LT; ContactsEntityBean＆GT; getContactDetails（
上下文mContext）{
ArrayList的＆LT; ContactsEntityBean＆GT; contactList =新的ArrayList＆LT; ContactsEntityBean＆GT;（）;
ContentResolver的CR = mContext.getContentResolver（）;
光标CUR = cr.query（ContactsContract.Contacts.CONTENT_URI，空，
NULL，NULL，NULL）;
如果（cur.getCount（）大于0）{
而（cur.moveToNext（））{
字符串ID = cur.getString（CUR
.getColumnIndex（ContactsContract.Contacts._ID））;
光标CUR1 = cr.query（
ContactsContract.CommonDataKinds.Email.CONTENT_URI，
空，ContactsContract.CommonDataKinds.Email.CONTACT_ID
+=？，新的String [] {
ID
}， 空值）;
而（cur1.moveToNext（））{
ContactsEntityBean contactsEntityBean =新ContactsEntityBean（）;
//获取联系人姓名
字符串名称= CUR1
.getString（CUR1
.getColumnIndex（ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME））;
// Log.e（姓名：，姓名）;
字符串email = CUR1
.getString（CUR1
.getColumnIndex（ContactsContract.CommonDataKinds.Email.DATA））;
// Log.e（电子邮件，电子邮件）;
contactsEntityBean.setName（名称）;
contactsEntityBean.setEmail（电子邮件）;
如果（电子邮件！= NULL）{
contactList.add（contactsEntityBean）;
}
}
cur1.close（）;
}
}
返回contactList;
}
此方法是，如果我有存储ABC @ gmail.com，ABC @ gmail.com为相同的用户，以便它返回abc@gmail.com&来自同一用户的回报倍数接触假设; abc@gmail.com 但我想只有一个记录abc@gmail.com
公共静态的ArrayList＆LT; SearchEntityBean＆GT; getContactEmailDetails（
上下文mContext）{
ArrayList的＆LT; SearchEntityBean＆GT; contactList =新的ArrayList＆LT; SearchEntityBean＆GT;（）;
尝试 {
ContentResolver的CR = mContext.getContentResolver（）;
光标CUR = cr.query（ContactsContract.Contacts.CONTENT_URI，空，
NULL，NULL，NULL）;
如果（cur.getCount（）大于0）{
而（cur.moveToNext（））{
字符串email =;
字符串ID = cur.getString（CUR
.getColumnIndex（ContactsContract.Contacts._ID））;
光标CUR1 = cr.query（
ContactsContract.CommonDataKinds.Email.CONTENT_URI，
空值，
ContactsContract.CommonDataKinds.Email.CONTACT_ID
+=？，新的String [] {
ID
}， 空值）;
SearchEntityBean contactsEntityBean =新SearchEntityBean（）;
而（cur1.moveToNext（））{
//获取联系人姓名
字符串名称= CUR1
.getString（CUR1
.getColumnIndex（ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME））;
串图象= CUR1
.getString（CUR1
.getColumnIndex（ContactsContract.CommonDataKinds.Phone.PHOTO_ID））;
字符串的邮件= CUR1
.getString（CUR1
.getColumnIndex（ContactsContract.CommonDataKinds.Email.DATA））;
如果（邮件！= NULL）{
如果（！mail.equalsIgnoreCase（登录preferenceClass
.getEmailID（mContext）））
电子邮件=邮件+邮件+，;
}
// Log.e（罗希特，电子邮件：+电子邮件）;
contactsEntityBean.setName（名称）;
contactsEntityBean.setImage（图像）;
}
如果（电子邮件！= NULL）{
如果（email.length（）大于0）{
如果（email.split（，）长度GT; 1）{
contactsEntityBean.setMutipleEmail（真正的）;
}
contactsEntityBean.setUserType（2）;
contactsEntityBean.setContactId（ID）;
contactsEntityBean.setEmail（电子邮件）;
contactList.add（contactsEntityBean）;
}
}
cur1.close（）;
}
}
}赶上（例外五）{
e.printStackTrace（）;
}
HashSet的＆LT; SearchEntityBean＆GT; HS =新的HashSet＆LT; SearchEntityBean＆GT;（）;
hs.addAll（contactList）;
contactList.clear（）;
contactList.addAll（HS）;
返回contactList;
}
解决方案
您应该修改 ContactsEntityBean 象下面这样
公共类ContactsEntityBean {
私人的HashSet＆LT;字符串＆GT;电子邮件=新的HashSet＆LT;字符串＆GT;（）;
公共无效setEmail（字符串电子邮件）{
如果（电子邮件== NULL）
返回;
this.emails.add（email.trim（））;
}
公众的HashSet＆LT;字符串＆GT; getEmails（）{
返回this.emails;
}
}
会在乎重复的电子邮件...您可以使用相同的逻辑地址，电话等。
更换你的 ContactsEntityBean 低于code
公共类ContactsEntityBean {
私人的HashSet＆LT;字符串＆GT;电子邮件;
私人的HashSet＆LT;字符串＆GT;手机;
私人的HashSet＆LT;字符串＆GT;地址;
私人字符串的ContactID;
私人布尔查= FALSE;
公共ContactsEntityBean（）{
this.emails =新的HashSet＆LT;字符串＆GT;（）;
this.phones =新的HashSet＆LT;字符串＆GT;（）;
this.addresses =新的HashSet＆LT;字符串＆GT;（）;
}
公众的HashSet＆LT;字符串＆GT; getPhones（）{
回电话;
}
公共无效setPhones（字符串手机）{
如果（电话== NULL）
返回;
this.phones.add（phone.trim（））;
}
公众的HashSet＆LT;字符串＆GT; getAddresses（）{
返回地址;
}
公共无效setAddresses（字符串地址）{
如果（地址== NULL）
返回;
this.addresses.add（address.trim（））;
}
公共无效setEmails（字符串电子邮件）{
如果（电子邮件== NULL）
返回;
this.emails.add（email.trim（））;
}
公众的HashSet＆LT;字符串＆GT; getEmails（）{
返回的电子邮件;
}
公共字符串getContactId（）{
返回的ContactID;
}
公共无效setContactId（字符串的ContactID）{
this.contactId =的ContactID;
}
公共布尔器isChecked（）{
返回检查;
}
公共无效setChecked（布尔检查）{
this.checked =检查;
}
}
和没有必要去关心重复。这会关心所有的东西..
please have a look :-
public static ArrayList<ContactsEntityBean> getContactDetails(
Context mContext) {
ArrayList<ContactsEntityBean> contactList = new ArrayList<ContactsEntityBean>();
ContentResolver cr = mContext.getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String id = cur.getString(cur
.getColumnIndex(ContactsContract.Contacts._ID));
Cursor cur1 = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null, ContactsContract.CommonDataKinds.Email.CONTACT_ID
+ " = ?", new String[] {
id
}, null);
while (cur1.moveToNext()) {
ContactsEntityBean contactsEntityBean = new ContactsEntityBean();
// to get the contact names
String name = cur1
.getString(cur1
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
// Log.e("Name :", name);
String email = cur1
.getString(cur1
.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
// Log.e("Email", email);
contactsEntityBean.setName(name);
contactsEntityBean.setEmail(email);
if (email != null) {
contactList.add(contactsEntityBean);
}
}
cur1.close();
}
}
return contactList;
}
this method is return multiple contact from same user suppose if i have stored abc@gmail.com,abc@gmail.com for same user so it is returning abc@gmail.com& abc@gmail.com but i want only one record abc@gmail.com
public static ArrayList<SearchEntityBean> getContactEmailDetails(
Context mContext) {
ArrayList<SearchEntityBean> contactList = new ArrayList<SearchEntityBean>();
try {
ContentResolver cr = mContext.getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI, null,
null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
String email = "";
String id = cur.getString(cur
.getColumnIndex(ContactsContract.Contacts._ID));
Cursor cur1 = cr.query(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID
+ " = ?", new String[] {
id
}, null);
SearchEntityBean contactsEntityBean = new SearchEntityBean();
while (cur1.moveToNext()) {
// to get the contact names
String name = cur1
.getString(cur1
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
String image = cur1
.getString(cur1
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_ID));
String mail = cur1
.getString(cur1
.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
if (mail != null) {
if (!mail.equalsIgnoreCase(LoginPreferenceClass
.getEmailID(mContext)))
email = email + mail + ",";
}
// Log.e("rohit", "Contact Email :" + email);
contactsEntityBean.setName(name);
contactsEntityBean.setImage(image);
}
if (email != null) {
if (email.length() > 0) {
if (email.split(",").length > 1) {
contactsEntityBean.setMutipleEmail(true);
}
contactsEntityBean.setUserType("2");
contactsEntityBean.setContactId(id);
contactsEntityBean.setEmail(email);
contactList.add(contactsEntityBean);
}
}
cur1.close();
}
}
} catch (Exception e) {
e.printStackTrace();
}
HashSet<SearchEntityBean> hs = new HashSet<SearchEntityBean>();
hs.addAll(contactList);
contactList.clear();
contactList.addAll(hs);
return contactList;
}
解决方案
You should modify your ContactsEntityBean like below
public class ContactsEntityBean {
private HashSet<String> emails = new HashSet<String>();
public void setEmail(String email) {
if (email == null)
return;
this.emails.add(email.trim());
}
public HashSet<String> getEmails() {
return this.emails;
}
}
Will care about duplicate emails... you can use same logic for addresses, phones etc.
Replace your ContactsEntityBean with below code
public class ContactsEntityBean {
private HashSet<String> emails;
private HashSet<String> phones;
private HashSet<String> addresses;
private String contactId;
private boolean checked = false;
public ContactsEntityBean() {
this.emails = new HashSet<String>();
this.phones = new HashSet<String>();
this.addresses = new HashSet<String>();
}
public HashSet<String> getPhones() {
return phones;
}
public void setPhones(String phone) {
if (phone == null)
return;
this.phones.add(phone.trim());
}
public HashSet<String> getAddresses() {
return addresses;
}
public void setAddresses(String address) {
if (address == null)
return;
this.addresses.add(address.trim());
}
public void setEmails(String email) {
if (email == null)
return;
this.emails.add(email.trim());
}
public HashSet<String> getEmails() {
return emails;
}
public String getContactId() {
return contactId;
}
public void setContactId(String contactId) {
this.contactId = contactId;
}
public boolean isChecked() {
return checked;
}
public void setChecked(boolean checked) {
this.checked = checked;
}
}
And no need to care about duplicates. this will care about all the things..
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