如何将图像转换为字节[] ............... [英] How to Convert Image in to the byte[]...............

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问题描述

我有Image并且我已经转换为字节...与notpad中可见的图像相同...我想要.......



  public   byte  [] imageToByteArray(System.Drawing.Image imageIn) 
{
MemoryStream ms = new MemoryStream();
imageIn.Save(ms,System.Drawing.Imaging.ImageFormat.Gif);
return ms.ToArray();
}



我知道但如何在上面的代码中传递图片,无法理解该代码,任何人都可以帮助我....

解决方案

尝试将图像转换为byte []:



  public   byte  [] ConvertImageToByteArray(Image imageIn)
{
var memoryStream = new MemoryStream();
imageIn.Save(memoryStream,ImageFormat.Jpeg);
memoryStream.Close();
return memoryStream.ToArray();
}





如果需要,可将其转换回图片:



  public  Image ConvertByteArrayToImage( byte  [] byteArrayIn )
{
var memoryStream = new MemoryStream(byteArrayIn);
var returnImage = Image.FromStream(memoryStream);
memoryStream.Close();
return returnImage;
}





希望有所帮助:)


一旦我想要功能性模拟器你的问题和我做过类似的事情。

这不是你问题的确切解决方案,但它可能会给你一个想法。

< pre lang =c#> private void btnBrowse_Click( object sender,EventArgs e)
{

OpenFileDialog ofd = new OpenFileDialog();
ofd.Title = 选择你的文件;

if (ofd.ShowDialog()== DialogResult.OK)
{
filepath = ofd.FileName。的ToString();
}
long size =( new FileInfo(filepath).Length);
FileStream fs = new FileStream(filepath,FileMode.Open,FileAccess.ReadWrite);
byte [] data = new byte < /跨度> [大小];

尝试
{
fs.Read(data, 0 ,( int )size);
// 这个来自FileStream的读取流fs并写入字节数组数据。
// 在这里获取data []字节数组。现在您可以根据您的要求使用它
}
catch (Exception ex)
{
MessageBox.Show( 文件读取错误... + ex.ToString());
}
最后
{
fs.Close();
fs.Dispose();
}

MemoryStream ms = new MemoryStream();
ms.Write(data, 0 ,( int )size);
// 您可以在这里获取新文件并将此内存流添加到其中。

destPath = Application.StartupPath.ToString()+ \\ images;
destPath = Path.Combine(destPath,Path.GetFileName(filepath));
File.Copy(filepath,destPath);

}





希望这个帮助


I have Image and I have convert into the byte... same as Image visible in notpad...that i want.......

public byte[] imageToByteArray(System.Drawing.Image imageIn)
{
 MemoryStream ms = new MemoryStream();
 imageIn.Save(ms,System.Drawing.Imaging.ImageFormat.Gif);
 return  ms.ToArray();
}


that i know but how to pass image in above code,can't understand that code,,can anyone help me please....

解决方案

Try this to convert image to byte[]:

public byte[] ConvertImageToByteArray(Image imageIn)
        {
            var memoryStream = new MemoryStream();
            imageIn.Save(memoryStream, ImageFormat.Jpeg);
            memoryStream.Close();
            return memoryStream.ToArray();
        }



And this to convert it back to Image if you need:

public Image ConvertByteArrayToImage(byte[] byteArrayIn)
        {
            var memoryStream = new MemoryStream(byteArrayIn);
            var returnImage = Image.FromStream(memoryStream);
            memoryStream.Close();
            return returnImage;
        }



Hope it helps :)


Once i wanted functionality similler to your problem and i have done something like this.
This is not exact solution to your problem but it may give you an idea.

private void btnBrowse_Click(object sender, EventArgs e)
{

        OpenFileDialog ofd = new OpenFileDialog();
        ofd.Title = "choose your file";

        if (ofd.ShowDialog() == DialogResult.OK)
        {
           filepath = ofd.FileName.ToString();
        }
        long size = (new FileInfo(filepath).Length);
        FileStream fs = new FileStream(filepath, FileMode.Open, FileAccess.ReadWrite);
        byte[] data = new byte[size];

        try
        {
           fs.Read(data, 0, (int)size);
           //This read stream from FileStream fs and write to byte array data.
           //Here you Get the data[] byte array. now you can use it as per your requirement
        }
        catch (Exception ex)
        {
            MessageBox.Show("error in file read..." + ex.ToString());
        }
        finally
        {
            fs.Close();
            fs.Dispose();
        }

        MemoryStream ms = new MemoryStream();
        ms.Write(data, 0, (int)size);
        //Here you can take new file and add this memory stream to it.

        destPath = Application.StartupPath.ToString() + "\\images";
        destPath = Path.Combine(destPath, Path.GetFileName(filepath));
        File.Copy(filepath, destPath);

}



Hope This help


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