打印W形状的星号 [英] Print Asterisk in W shape

问题描述

伙计们，我想用W形打印星号。我似乎无法弄明白。一直在谷歌上寻找它。请帮忙。代码必须是C语言。 （我对编程比较陌生）

 * * 
 
 * * 
 
 * * * 
 
 * * * * 
 
 * * 
 

更新:(这里没有正确显示形状）



添加了代码块（它显示的是现在形状正确） - OriginalGriff [/ edit]

解决方案

使用标准函数printf编写非常简单

  int  printf（ const   char  * format，...）; 

将格式化数据打印到stdout

将格式指向的C字符串写入标准输出（stdout） 。如果format包含格式说明符（以％开头的子序列），格式化后的其他参数将被格式化并插入到结果字符串中，替换它们各自的说明符。

  #include   <   stdio。 h  >  
  
  int  main（ ）
 {
 
 printf（  * * \ n）; 
 printf（  \ n）; 
 printf（  * * \ n）; 
 printf（  \ n）; 
 printf（  * * * \ n）; 
 printf（  \ n）; 
 printf（  * * * * \ n）; 
 printf（  \ n）; 
 printf（  * * \ n）; 
 
  return   0 ; 
} 

问候，

Alex

因为它是C，你应该使用< pre lang =c ++> printf（ theline \ n）;

每一行。



所以，这应该是最终的样子：

  #include   <   stdio.h  >  
   #include   <   conio.h  >  
  
  int  main（）{
 printf（   * * \ n）; 
 printf（  * * \ n）; 
 printf（  * * * \ n）; 
 printf（  * * * * \ n）; 
 printf（  * * \ n）; 
 getch（）;  //  如果您不使用某些输入功能，程序将退出而不让您看到验证 
  return   0 ; 
} 

Guys, I want to print asterisk in W shape. I can't seem to figure it out. Been looking for it all over Google as well. Need help, please. The code has to be in C language. (I'm relatively new to programming)

*         *

*         *

*    *    *

*  *   *  *

*         *

Update: (It's not displaying the shape correctly here)

[edit]Code block added (it's displaying the shape properly now) - OriginalGriff[/edit]

解决方案

It is very easy to write using standard function printf

int printf ( const char * format, ... );

Print formatted data to stdout
Writes the C string pointed by format to the standard output (stdout). If format includes format specifiers (subsequences beginning with %), the additional arguments following format are formatted and inserted in the resulting string replacing their respective specifiers.

#include <stdio.h>

int main()
{

    printf("*         *\n");
    printf("           \n");
    printf("*         *\n");
    printf("           \n");
    printf("*    *    *\n");
    printf("           \n");
    printf("*  *   *  *\n");
    printf("           \n");
    printf("*         *\n");

    return 0;
}

Regards,
Alex

Since it's C, you should use

printf("theline\n");

for each line.

So, that's how it should finally look:

#include<stdio.h>
#include<conio.h>

int main(){
  printf("*       *\n");
  printf("*       *\n");
  printf("*   *   *\n");
  printf("* *   * *\n");
  printf("*       *\n");
  getch(); //if you don't use some input function, the program will exit without letting you see the tesult
  return 0;
}

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