我必须反序列化下面的xml文件。什么应该是这个类？请帮忙。 [英] I have to deserialize the below xml file. What should be the class for this? Please help.

问题描述

<validationrule>
  <fieldname>
    <entitytype>02</entitytype>
    <name>PANRangeLow</name>
    <isrequired>True</isrequired>
    <isrequirederrormessage>PAN Range Low is required</isrequirederrormessage>
    <datatype>Number</datatype>
    <datatypeerrormessage>PAN Range Low must be numeric</datatypeerrormessage>
</fieldname>
  <fieldname>
    <entitytype>02</entitytype>
    <name>PANRangeHigh</name>
    <isrequired>True</isrequired>
    <isrequirederrormessage>PAN Range High is required</isrequirederrormessage>
    <datatype>Number</datatype>
    <datatypeerrormessage>PAN Range High must be numeric</datatypeerrormessage>
  </fieldname>
</validationrule>

推荐答案

XMLSerializer 带 XMLReaderSettings 应该给你一个解决方案。

尝试这个提示 - XML序列化和反序列化 [ ^ ]。

XMLSerializer with XMLReaderSettings should give you a solution.
Try this tip - XML Serialization and Deserialization[^].

你可以试试这个。我从这里找到了解决方案 http://stackoverflow.com/questions/4203540/generate- c-sharp-class-from-xml [ ^ ]

You can try this. I found the solution from here http://stackoverflow.com/questions/4203540/generate-c-sharp-class-from-xml[^]

/// <remarks />
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
    public partial class validationrule
    {

        private validationruleFieldname[] fieldnameField;

        /// <remarks />
        [System.Xml.Serialization.XmlElementAttribute("fieldname")]
        public validationruleFieldname[] fieldname
        {
            get
            {
                return this.fieldnameField;
            }
            set
            {
                this.fieldnameField = value;
            }
        }
    }

    /// <remarks />
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
    public partial class validationruleFieldname
    {

        private byte entitytypeField;

        private string nameField;

        private string isrequiredField;

        private string isrequirederrormessageField;

        private string datatypeField;

        private string datatypeerrormessageField;

        /// <remarks />
        public byte entitytype
        {
            get
            {
                return this.entitytypeField;
            }
            set
            {
                this.entitytypeField = value;
            }
        }

        /// <remarks />
        public string name
        {
            get
            {
                return this.nameField;
            }
            set
            {
                this.nameField = value;
            }
        }

        /// <remarks />
        public string isrequired
        {
            get
            {
                return this.isrequiredField;
            }
            set
            {
                this.isrequiredField = value;
            }
        }

        /// <remarks />
        public string isrequirederrormessage
        {
            get
            {
                return this.isrequirederrormessageField;
            }
            set
            {
                this.isrequirederrormessageField = value;
            }
        }

        /// <remarks />
        public string datatype
        {
            get
            {
                return this.datatypeField;
            }
            set
            {
                this.datatypeField = value;
            }
        }

        /// <remarks />
        public string datatypeerrormessage
        {
            get
            {
                return this.datatypeerrormessageField;
            }
            set
            {
                this.datatypeerrormessageField = value;
            }
        }
    }

应该使用XMLSerializer类。



您可以尝试类似

Should use XMLSerializer class .

You can try something like

[Serializable()]
public class FieldName
{
    [System.Xml.Serialization.XmlElement("EntityType")]
    public string EntityType { get; set; }

    [System.Xml.Serialization.XmlElement("Name")]
    public string Name { get; set; }

    ...
}

[Serializable()]
[System.Xml.Serialization.XmlRoot("validationrule")]
public class validationrules
{
    [XmlArray("FieldName")]
    [XmlArrayItem("FieldName", typeof(FieldName))]
    public FieldName[] fieldNames { get; set; }
}

// the below code may be added into your deserialize method
validationrule rules= null;
string path = "xmlpath.xml";

XmlSerializer serializer = new XmlSerializer(typeof(validationrules));

using (XmlReader reader = XmlReader.Create(path))
    {
        rules =  serializer.Deserialize(reader) as validationrules;
    }

希望这有帮助

Hope this helps

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