命名样式和模板 [英] Naming of styles and templates

问题描述

在Blend4或Blend5中打开的WPF项目中，我在usercontrol中使用以下元素。 style属性设置为"HLK_Klappe"

In an WPF project opened in Blend4 or Blend5 I am using the following element in an usercontrol. The style property is set to "HLK_Klappe"

<vih:VisuState x:Name="Shutter_Invert" Content="xxx" Margin="549,59,0,0" VerticalAlignment="Top" Style="{DynamicResource HLK_Klappe}" Height="80" Width="32" State="{Binding SelectedValue.Key, ElementName=StatesList}" Status="{Binding SelectedValue.Key, ElementName=StatusList}" CmdPriority="{Binding SelectedValue.Key, ElementName=PriorityList}" Invert="True" HorizontalAlignment="Left"/>

如果我使用bredcrumb tabcontrol，我会看到以下代码：

In the If I use the bredcrumb tabcontrol, I see the following code:

    <Style x:Key="HLK_Klappe" TargetType="{x:Type vih:VisuState}">
        <Setter Property="Width" Value="32"/>
        <Setter Property="Height" Value="88"/>
        <Setter Property="Template">
            <Setter.Value>
                <ControlTemplate TargetType="{x:Type vih:VisuState}">

....

但是如果我在设计师视图中使用编辑模板 - 应用资源，我会看到" <强> HLKKlappe "缺少下划线（_）。

But if I use Edit Template - Apply Resource in the designer view, I see "HLKKlappe" with missing underscore (_).

这段文字的来源是什么，为什么是下划线（_）缺少？

推荐答案

我认为这是因为_字符用于表示菜单项的加速键。例如，文件菜单被定义为"_File"，编辑为"_Edit"，等等。由于您的样式名称用作菜单文本，因此它可能会将_ b $ b解释为_，就好像它应该表示加速键一样。 

I believe this is because the _ character is used to denote the accelerator key for a menu item. For example, the file menu is defined as "_File", edit as "_Edit", and so on. Because the name of your style is used as the menu text, it likely interprets the _ as if it should denote the accelerator key. 

这篇关于命名样式和模板的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！