C ++到C＃ - 将无符号Char []转换为无符号长[] [英] C++ to C# - Casting Unsigned Char[] to Unsigned Long[]

问题描述

亲爱的开发者，



我正在努力将一些C ++代码转换为C＃。不幸的是老实说你，我不是很熟悉C ++，所以也许我错过了一些简单的东西。



无论如何，我有这个64元素的无符号字符使用以下元素调用 buffer ：



[0] ='C'

[1] =' P'

[2] ='0'

[3] ='4'

...

[12] ='€'



剩下的元素都是\0（不是'0'）。



然后将这个unsigned char数组转换为unsigned long数组（在类中），如下所示：

Dear fellow devs,

I'm working on a task of converting some C++ code into C# . Unfortunately to be honest with you, I'm not very fluent with C++ so maybe I'm missing something simple.

Anyway, I have this unsigned char of 64 elements called buffer with the following elements:

[0] = 'C'
[1] = 'P'
[2] = '0'
[3] = '4'
...
[12] = '€'

The rest of the elements are all \0 (not '0').

Then this unsigned char array is cast to unsigned long array (within a class) as follows:

typedef struct _SHA_MSG {
    unsigned long W[80];
} sha1_key;

unsigned char buffer[64]={0};

buffer[0] = 'C';
buffer[1] = 'P';
buffer[2] = '0';
buffer[3] = 4 + '0';
buffer[12] = 0x80;

sha1_key* k = (sha1_key*)buffer;

但是在这一点上，它会发生巨大变化！例如 kW 包含：



[0] = 875581507

[3] = 128

[16] = 3435973836

[17] = 2641335238

[18] = 3865956

[19] = 18366288

[20] = 0

[21] = 0

[22] = 2130567168

[23] = 3435973836



等，大多数元素的值为0或3435973836.



刚刚发生了什么？有人可以指示任何产生这些结果的C＃等效操作（理想情况下不依赖于IntPtr）吗？



非常感谢！



编辑：



这部分我的C＃代码是：

However at this point, it changes drastically! For example k.W contains :

[0] = 875581507
[3] = 128
[16] = 3435973836
[17] = 2641335238
[18] = 3865956
[19] = 18366288
[20] = 0
[21] = 0
[22] = 2130567168
[23] = 3435973836

etc, with most elements having value 0 or 3435973836.

What has just happened? Can someone kindly instruct any C# equivalent of this operation that yields these results (ideally without relying on IntPtr) ?

Thanks a lot!



My C# code of this part is:

struct sha1_key
{
    uint[] w;

    public uint[] W
    {
        get { return w; }
        set { w = value; }
    }
}

sha1_key key = new sha1_key();
key.W[0] = 'C';
key.W[1] = 'P';
key.W[2] = '0';
key.W[3] = (char)(year + '0');

key.W[12] = (char)0x80;

正如您所看到的，到目前为止，我保留了大部分代码，就像在C ++中一样。稍后，当我设法让它工作时，我会改进它：）

As you can see, I have so far retained much of the code as it is in C++. I will improve upon it later, when I manage to get it working :)

推荐答案

在C ++中， unsigned char type是单个字节。如果将指向 unsigned char 的数组的指针强制转换为指向 unsigned long 数组的指针，则表示您正在查看内存好像被组织成32位字而不是单字节。



kW 包含875581507，这是十六进制的34305043。从最低有效字节开始，对应于原始 unsigned char 数组中的 [0] 个字节，有43（'C'），50（'P'），30（'0'）和34（'4'）。

In C++, the unsigned char type is a single byte. If you cast the pointer to an array of unsigned char to a pointer to an array of unsigned long, you are viewing the memory as if it were organized into 32-bit words instead of single bytes.

k.W contains 875581507, which is 34305043 in hexadecimal. Starting from the least significant byte, which corresponds to the [0]th byte in the original unsigned char array, you have 43 ('C'), 50 ('P'), 30 ('0'), and 34 ('4').

对于ascii字符

For ascii characters

byte[] bytes = { (byte) 'C', (byte) 'P', (byte) '0', (byte) '0' + 4 };

 UInt32 i = BitConverter.ToUInt32(bytes, 0);

http://msdn.microsoft.com/en-us/library/system.bitconverter.touint32.aspx [ ^ ]

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