如何在datagridview中选择行时打开表单 [英] How to open form when row is selected in datagridview

问题描述

请尝试编写此方案的代码。我设计了一个datagridview，它从数据库（SQL服务器）加载数据。现在我想总是点击datagridview中的一行来以弹出形式显示内容。例如，我单击一行，然后显示更新表单。

我在WPF中很容易做到这一点但是当我尝试在winform中执行此操作时我感到头疼。

任何帮助都将受到赞赏。谢谢

Hi,
Please I have trying to code this scenario. I have designed a datagridview which loads data from a database (SQL server). Now I want to always click on a row in the datagridview to show the content in pop-up form. For instance I click on a row and an update form shows.
I do this easily in WPF but I have headaches when I try to do this in winform.
Any help will be appreciated. Thanks

推荐答案

您将需要一个DataGrid点击事件（DoubleClick或CellClick），并将您的弹出窗口显示为对话框> ShowDialog（）

You will need a DataGrid click event (DoubleClick or maybe CellClick) and show your popup as a dialog > ShowDialog()

private void DataGrid_DoubleClick(object sender, EventArgs e)
{
 PopUpForm popupform = new PopUpForm(Pass Parameter);
 popupform.ShowDialog(); 
 //Reload you DataGrid here
}

你要传递的参数应该在你的PopUpForm上定义，比如

Parameter you are going to pass should be defined on your PopUpForm like

public PopUpForm (type Parameter)
{
 InitializeComponent();
 parameter = Parameter; // assuming parameter is defined
}

希望有帮助

Hope it helps

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