如何在mvc中动态显示模型的属性？ [英] How to show the model's attribute dynamically in mvc?

问题描述

现在我可以显示和更新模型，如果我知道它的名称和值。例如，学生模型是这样的。

Now I can show and update a model if I know its name and value.For example,a studentmodel is like this.

public class student{
public string Name{ge;set}
public bool Sex{ge;set}
public bool Address{ge;set}
}
 @Html.TextBoxFor(model => model.Name)

 @Html.TextBoxFor(model => model.Sex)

 @Html.TextBoxFor(model => model.Address)

我想展示和更新模型，但我不知道有多少addAttribute和什么名字和va模型的lue？例如，如果我将一个Model返回给视图，模型是关于Fruit的，我想显示和更新它的属性，如price，Weight，如果我将一个Model返回给视图，模型是关于Student的，我想显示和更新他的属性，如姓名，性别和地址。

I want to show and update a model,but I do not know how many addAttribute and what name and value of the model？For example,If I return a Model to the view,the model is about Fruit,I want to show and update its attribute like price,Weight,If I return a Model to the view,the model is about Student,I want to show and update his attribute like name and sex and address.

推荐答案

创建两个部分视图，一个返回FruitModel的类型，其他类型为StudentModel并且在主视图中你不需要指定ViewModel类。在ActionResult中将ViewData或ViewBag中的状态设置为fruitModel或StudentModel。

Create two partial views one to return the type of FruitModel and other be the type of StudentModel and in the main view you no need to specify a ViewModel class.In the ActionResult set a status in ViewData or ViewBag as fruitModel or StudentModel.

public ActionResult Action()
{
if(it's studentModel)
   ViewData["Status"]=1
else
 ViewData["Status"]=2
return View();
}

之后从视图中可以返回基于viewData值的局部视图，如下所示。

After that from the view you can return the partial view based on the viewData value like below.

@if(Viewdata["Status"]==2)
Html.RenderPartial( "FirstPartialView")
else
Html.RenderPartial( "SecondPartialView")

希望这有助于

Hope this helps

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