受保护的成员访问继承 [英] protected member access in inheritance

问题描述

我可以通过派生类的对象初始化基类的受保护成员而不提供其set和get属性吗？

Can I initialize a protected member of the base class through the object of the derived class without providing its set and get properties?

推荐答案

是 - 并且没有。

您可以在派生类中访问它：

Yes - and no.
You can access it in the derived class:

public class Base
    {
    protected string myString;
    }
public class Derived : Base
    {
    public Derived()
        {
        myString = "Hello World";
        }
    }

但您无法通过实例对象从外部访问它：

but you can't access it from outside either via the instance object:

private void MyMethod()
    {
    Derived d = new Derived();
    d.myString = "goodbye";  //'MyNameSpace.Base.myString' is inaccessible due to its protection level
    }

除非你将它封装在一个属性中并指定setter和getter：

Unless you encapsulate it in a property and specify the setter and getter:

private void MyMethod()
        {
        Derived d = new Derived();
        d.MyString = "goodbye";   //All fine
        }
    ...
public class Base
    {
    protected string myString;
    }
public class Derived : Base
    {
    public string MyString { get { return myString; } set { myString = value; } }
    public Derived()
        {
        myString = "Hello World";
        }
    }

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