将带有连接的SQL Select语句转换为LINQtoSQL查询 [英] Converting a SQL Select Statement with Joins to a LINQtoSQL query
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问题描述
我一直在尝试将SQL语句(下面)转换为LINQtoSQL语句。我开发了一种可怕的解决方法,但效率低得令人难以置信。有没有人知道怎么做而没有一切可怕?
SQL Select声明:
I've been trying to transform a SQL Statement (below) to a LINQtoSQL statement. I developed a horrible workaround, but it's incredible inefficient. Does anyone know how to do it without all horribleness?
SQL Select Statement:
SELECT DISTINCT locationGroups.*
FROM locationGroups
JOIN locations
ON locationGroups.locationGroupID = locations.locationGroup
JOIN locationRegions
ON locations.region = locationRegions.regionID
WHERE locationRegions.regionID = 34
我可怕的c#代码:
My horrible c# code:
public List<locationGroup> GetLocationGroups(locationRegion locationRegion)
{
#region Inefficent code
using (var context = new Entities())
{
location[] lA = context.locations.Where(location => location.region == locationRegion.regionID).ToArray();
List<locationGroup> lG = new List<locationGroup>();
foreach (location l in lA)
{
if (lG.Any(list => list.locationGroupID == l.locationGroup) == false)
lG.Add(context.locationGroups.FirstOrDefault(locationGroup => locationGroup.locationGroupID == l.locationGroup));
}
return lG;
}
#endregion
}
推荐答案
我发现这个网站在使用linq时非常有用 101 Linq样本 [ ^ ]
那里有一些连接示例
I find this site most useful when faffing around with linq 101 Linq samples[^]
There are some join examples in there
我去了Mycroft Holmes建议的网站,过了一段时间我终于建了一些有用的东西。我在下面发布了解决方案,以供其他在这个问题上需要帮助的人参考。
I went to Mycroft Holmes suggested site and after awhile I finally built something that worked. I posted the solution below for reference to anyone else who needs help on this issue.
using (var context = new iomniEntities())
{
List<locationGroup> lLG = new List<locationGroup>();
lLG = (from lG in context.locationGroups
join l in context.locations on lG.locationGroupID equals l.locationGroup
join lR in context.locationRegions on l.region equals lR.regionID
where (l.locationTypeID == 9 || l.locationTypeID == 11) && l.active == true && lR.regionID == locationRegion.regionID
select lG).Distinct().ToList<locationGroup>();
return lLG;
}
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