将数据保存到XML文件时出现问题 [英] Problem in saving data to an XML file

问题描述

我正在用C＃编写程序，将一些数据保存到XML文件中。我有3个问题。



1.我正在尝试将我的帐户详细信息保存在XML文件中。我要保存的数据是帐户名，用户名，密码和附加信息（多行）。但我不知道如何正确地将数据安排到XML元素中。我需要一些帮助。



2.我使用下面的代码将数据保存到XML文件中。但是当我尝试保存另一条记录时，它会从XML文件中删除现有数据，然后添加新记录。所以现在我只有一个记录。我该如何解决？

  private   void  button1_Click（ object  sender，EventArgs e）
 {
  if （Functions.SavetoXML（textBox1.Text，textBox2.Text，textBox3.Text，textBox4.Text）==  true ）
 { 
 XmlWriterSettings settings =  new  XmlWriterSettings（）; 
 settings.Indent =  true ; 
 
 XmlWriter writer = XmlWriter.Create（  Passwords.rar，设置）; 
 writer.WriteStartDocument（）; 
 writer.WriteComment（ 此文件由PasswordSave生成。）; 
 writer.WriteStartElement（  Account）; 
 writer.WriteElementString（ 名称，   + textBox1.Text）; 
 writer.WriteElementString（ 用户名，   + textBox2.Text）; 
 writer.WriteElementString（ 密码，   + textBox3.Text）; 
  //   writer.WriteStartElement（Additinal Info，+ textBox4.Text）;  
 writer.WriteEndElement（）; 
 writer.WriteEndDocument（）; 
 
 writer.Flush（）; 
 writer.Close（）; 
 MessageBox.Show（ 信息已保存！， 完成，MessageBoxButtons.OK，MessageBoxIcon.Information）; 
} 
} 

3.保存其他信息时，我必须在XML元素中保存多行信息，我该如何实现？



谢谢。

解决方案

你可以用Write CDATA ....

 writer.WriteElementString（  AdditinalInfo）; 
 
  //  写CDATA。 
 writer.WriteCData（< span class =code-string> 在这里写下你的多行文字）; 

根据以上描述，您似乎需要在XML文件中附加帐户详细信息，以便您可以按照您的工作方式执行此操作：
 
 using System .Xml.Linq; 
 
 private void button1_Click（object sender，EventArgs e）
 {
 string _File =C：/Test.XML; 
 if（！File.Exists（_File））
 {
 XmlWriterSettings settings = new XmlWriterSettings（）; 
 settings.Indent = true; 
 XmlWriter writer = XmlWriter.Create（_File，settings）; 
 writer.WriteStartDocument（）; 
 writer.WriteComment（此文件由PasswordSave生成。）; 
 writer.WriteStartElement（Accounts）; 
 writer.WriteStartElement（Account）; 
 writer.WriteElementString（Name，+ textBox1.Text）; 
 writer.WriteElementString（Username，+ textBox2.Text）; 
 writer.WriteElementString（Password，+ textBox3.Text）; 
 writer.WriteEndElement（）; 
 writer.WriteEndElement（）; 
 writer.Close（）; 
 
} 
 else 
 {
帐户（_File，textBox1.Text，textBox2.Text，textBox3.Text）; 
} 
} 
 
 public void帐户（字符串文件，字符串名称，字符串用户名，字符串密码）
 {
 XDocument doc = XDocument.Load（文件）; 
 XElement xeName = new XElement（Account，new XElement（Name，name），new XElement（Username，Username），new XElement（Password，Password））; 
 doc.Element（Accounts）。Add（xeName）; 
 doc.Save（file）; 
} 

我建议使用XmlDocument或XDocument类来创建XML而不是XmlWriter.It将简化您的XML工作：）

Hi, I'm coding a program in C# to save some data in to an XML file. I have 3 questions.

1. I'm trying to save my account details in the XML file. The data I want to save is, Account name, Username, Password and Additional info(multiple lines). But I don't know how to arrange the data correctly in to XML elements. I need some help with that.

2. I'm using below code to save data to the XML file. But when I try to save another record, it deletes the existing data from the XML file and then add the new record. So now I have only one record. How do I fix it?

private void button1_Click(object sender, EventArgs e)
        {
            if (Functions.SavetoXML(textBox1.Text, textBox2.Text, textBox3.Text, textBox4.Text) == true) 
            {
                XmlWriterSettings settings = new XmlWriterSettings();
                settings.Indent = true;

                XmlWriter writer = XmlWriter.Create("Passwords.rar", settings);
                writer.WriteStartDocument();
                writer.WriteComment("This file is generated by PasswordSave.");
                writer.WriteStartElement("Account");
                writer.WriteElementString("Name", "" + textBox1.Text);
                writer.WriteElementString("Username", "" + textBox2.Text);
                writer.WriteElementString("Password", "" + textBox3.Text);
               // writer.WriteStartElement("Additinal Info", "" + textBox4.Text);
                writer.WriteEndElement();
                writer.WriteEndDocument();

                writer.Flush();
                writer.Close();
                MessageBox.Show("Information Saved!", "Done", MessageBoxButtons.OK, MessageBoxIcon.Information);
            }
        }

3. When saving additional info, I have to save multiple lines of information in a XML element how can I achieve that?

Thanks.

解决方案

You could use Write CDATA....

writer.WriteElementString("AdditinalInfo");

// Write CDATA.
writer.WriteCData("write your multi-line text here");

As per above description it seems u need to append account details in XML file so You can do this in this way as per your work:

using System.Xml.Linq;

private void button1_Click(object sender, EventArgs e)
        {
            string _File="C:/Test.XML";
            if (!File.Exists(_File))
            {
                XmlWriterSettings settings = new XmlWriterSettings();
                settings.Indent = true;
                XmlWriter writer = XmlWriter.Create(_File, settings);
                writer.WriteStartDocument();
                writer.WriteComment("This file is generated by PasswordSave.");
                writer.WriteStartElement("Accounts");
                writer.WriteStartElement("Account");
                writer.WriteElementString("Name", "" + textBox1.Text);
                writer.WriteElementString("Username", "" + textBox2.Text);
                writer.WriteElementString("Password", "" + textBox3.Text);
                writer.WriteEndElement();
                writer.WriteEndElement();
                writer.Close();
              
            }
            else
            {
                Account(_File, textBox1.Text,textBox2.Text,textBox3.Text);
            }
      }

public void Account(string file,string name, string Username, string Password)
        {
           XDocument doc = XDocument.Load(file);
           XElement xeName = new XElement("Account", new XElement("Name", name), new                XElement("Username", Username), new XElement("Password", Password));
           doc.Element("Accounts").Add(xeName);
           doc.Save(file);
        }

I Suggest use XmlDocument or XDocument classes to create XML as well instead of XmlWriter.It will ease your XML working.:)

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