Visual Basic中的输入不匹配异常 [英] Input Mismatch Exception in Visual Basic
本文介绍了Visual Basic中的输入不匹配异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我不熟悉Visual Basic中的异常处理。下面我有一个带有for-loop的代码片段。我的目标是在用户输入字符串而不是整数时抛出异常。如果有人能告诉我正确的try catch语句来实现这一目标,我将不胜感激。
I'm not familiar with exception handling in Visual Basic. Below I have a code snippet with my for-loop. My goal is to throw an exception if the user inputs a string instead of an integer. I would greatly appreciate if someone could show me the correct try catch statement to accomplish this.
For rowindex = 1 To myDataGridView.RowCount
For columnindex = 1 To myDataGridView.ColumnCount
objWorkSheet.Cells(rowindex + 14, columnindex + 0) = myDataGridView(columnindex - 1, rowindex - 1).Value
Next
Next
推荐答案
你需要这样的东西,
例如:
Hi,
you need something like this,
For example:
Dim inputs As String() = {"1", "2", "3", "tr", "6", "tt", "500", "343", "AA"}
Dim invalidinput As New List(Of String)
Dim validinput As New List(Of String)
For index = 0 To 10
If (IsvalidNumber(inputs(index)) = True) Then
invalidinput.Add(inputs(index))
Else
validinput.Add(inputs(index))
End If
Next
If (invalidinput.Count > 0) Then
' do your stuff
End If
If (validinput.Count > 0) Then
' do your stuff
End If
用户定义的功能:
User defined function:
Public Function IsvalidNumber(ByVal value As Integer) As Boolean
Dim flag As Boolean = False
Dim number As Integer
Try
number = Convert.ToInt32(value)
flag = True
Catch ex As Exception
' Do nothing
End Try
Return flag
End Function
问候和感谢
Sarva
Regards and thanks
Sarva
请不要请不要抛出异常的用户输入错误。除非您正在编写DLL或其他无法与用户交互的其他内容,否则抛出异常是不对的。您应验证用户输入,如果错误,请告诉用户并要求他们更正。
错误处理异常导致应用程序崩溃,异常并不意味着用这种方式。只需使用消息框并停止处理,直到错误得到修复。
Please, please please do not throw exceptions for incorrect user input. Unless you are writing a DLL or something else that does not have any way of interacting with the user, throwing an exception is the wrong thing to do. You should validate the user input and if its wrong, tell the user and ask them to correct it.
Incorrectly handled exceptions cause application crashes, and exceptions are not meant to be used this way. Just use a message box and stop processing until the error is fixed.
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