如何使用Xslt从Xml中删除节点 [英] How to remove a node from Xml using Xslt
问题描述
使用Xslt，如何删除< Date>来自以下Xml的节点：
< TheXml>
< ThePhrases>
&NBSP; <短语>
&NBSP; &NBSP; < PhraseCode> test< / PhraseCode>
&NBSP; &NBSP; < PhraseData File =" text.xml" QC ="1">
&NBSP; &NBSP; &NBSP; <金额> $ 113,110.00< /金额>
&NBSP; &NBSP; &NBSP; < Date> 4-22-1985< / Date>
&NBSP; &NBSP; < / PhraseData>
&NBSP; < / Phrase>
< / ThePhrases>
< / TheXml>
我试图得到以下结果：
< TheXml>
< ThePhrases>
&NBSP; <短语>
&NBSP; &NBSP; < PhraseCode> test< / PhraseCode>
&NBSP; &NBSP; < PhraseData File =" text.xml" QC ="1">
&NBSP; &NBSP; &NBSP; <金额> $ 113,110.00< /金额>
&NBSP; &NBSP; < / PhraseData>
&NBSP; < / Phrase>
< / ThePhrases>
< / TheXml>
这就像
< xsl：template match =" @ * |节点（）">
< xsl：copy>
< xsl：apply-templates select =" @ * |节点（）" />
< / xsl：copy>
< / xsl：template>
< xsl：template match =" PhraseData / Date" />
这将确保任何"日期"。任何"PhraseData"的子元素。元素被删除，当然根据您的需要，你可以收紧条件，例如。
< xsl：template match =" PhraseData [@File ='text.xml'] / Date" />
Using Xslt, how can I remove the <Date> node from the Xml below:
<TheXml>
<ThePhrases>
<Phrase>
<PhraseCode>test</PhraseCode>
<PhraseData File="text.xml" QC="1">
<Amount>$113,110.00</Amount>
<Date>4-22-1985</Date>
</PhraseData>
</Phrase>
</ThePhrases>
</TheXml>
I am trying to get the below result:
<TheXml><ThePhrases>
<Phrase>
<PhraseCode>test</PhraseCode>
<PhraseData File="text.xml" QC="1">
<Amount>$113,110.00</Amount>
</PhraseData>
</Phrase>
</ThePhrases>
</TheXml>
That is as easy as
<xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> <xsl:template match="PhraseData/Date"/>
That would make sure any "Date" child elements of any "PhraseData" elements are removed, of course depending on your needs you can tighten the conditon as with e.g.
<xsl:template match="PhraseData[@File = 'text.xml']/Date"/>
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