使用Multipart表单数据进行文件上载的Web服务 [英] Webservice for file upload using Multipart form data

问题描述

我面临着如何使用多部分表单数据使用TransferFile（）方法的Web服务的关键问题？

我已经为它编写了以下代码：

< pre lang =c＃> [WebMethod]
[ScriptMethod（ResponseFormat = ResponseFormat.Json）]
public void TransferFile（）
{

HttpContext postedContext = HttpContext.Current;
HttpFileCollection Request = postingContext.Request.Files;
foreach （HttpPostedFile item in Request）
{
string filename = item.FileName;

byte [] fileBytes = new 字节 [item.ContentLength];
item.InputStream.Read（fileBytes， 0 ，item.ContentLength）;
TransferFile（filename，fileBytes）;

// objFileTransfer.TransferFile（filename，fileBytes）;
retJSON = js.Serialize（ new {Result = objFileTransfer.TransferFile（filename，fileBytes）}）;
Context.Response.Write（retJSON）;
// fileBytes现在包含文件内容
// 文件名包含文件名
}
}

这个网络服务是否获得多部分表单数据？

当iPhone开发人员使用此API时，他们没有得到回复。

  private  FtpWebRequest ftpRequest =  null ; 
  //   private FtpWebResponse ftpResponse = null;  
  private 流ftpStream =  null ; 
  private   int  bufferSize =  2048 ; 
 
  public   string  TransferFile（ string  filename， byte  [] fileContent）
 {
  string  strMsg =  string  .Empty; 
 尝试 
 {
 
  / *  创建FTP请求* /  
 字符串 uploadUrl = 字符串 .Format（  {0} / {1} / {2}，< span class =code-string>  ftp：// Address，  DirectoryName，filename）; 
 ftpRequest =（FtpWebRequest）FtpWebRequest.Create（uploadUrl）; 
  / *  使用提供的用户名和密码登录FTP服务器* /  
 ftpRequest.Credentials =  new  NetworkCredential（ 用户名， 密码）; 
  / *  如有疑问，请使用以下选项* /  
 ftpRequest.UseBinary =  true ; 
 ftpRequest.UsePassive =  true ; 
 ftpRequest.KeepAlive =  true ; 
  / *  指定FTP请求的类型* /  
 ftpRequest.Method = WebRequestMethods.Ftp.UploadFile; 
 尝试 
 {
 
 ftpRequest.ContentLength = fileContent.Length; 
 
流requestStream = ftpRequest.GetRequestStream（）; 
 requestStream.Write（fileContent， 0 ，fileContent.Length）; 
 requestStream.Close（）; 
 FtpWebResponse response =（FtpWebResponse）ftpRequest.GetResponse（）; 
 strMsg =  文件上传状态： + response.ToString（）; 
 
} 
  catch （Exception ex）{Console.WriteLine（ex.ToString（））; } 
  / *  资源清理* /  
 ftpStream.Close（）; 
 ftpRequest =  null ; 
} 
  catch （Exception ex）{Console.WriteLine（ex.ToString（））; } 
  return  strMsg; 
 
} 

解决方案

Hello Rajesh，



以下是示例代码。当点击提交按钮时，它会将所选文件数据发布到提到的（动作）网站。

 <  表单    id   =  Form1   < span class =code-attribute> action   =  htt：//mysite.com/photo    方法  = < span class =code-keyword> post    enctype   =  multipart / form-data >  
 <  输入    id   =  myPhoto    name   =  myPhoto    type   =  file    /  >  
 <   input     type   = 提交    /  >  
 <   / form  >  

谢谢，

Imdadhusen

请检查答案 - WCF服务接受邮政编码的multipart / form-data [ ^ ]。



这可能对你有帮助。

I am facing critical problem that How to make webservice that uses TransferFile() method by multipart form data?.
I have write following code for it:

[WebMethod]
        [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
        public void TransferFile()
        {

            HttpContext postedContext = HttpContext.Current;
            HttpFileCollection Request = postedContext.Request.Files;
            foreach (HttpPostedFile item in Request)
            {
                string filename = item.FileName;

                byte[] fileBytes = new byte[item.ContentLength];
                item.InputStream.Read(fileBytes, 0, item.ContentLength);
                TransferFile(filename, fileBytes);

                //objFileTransfer.TransferFile(filename, fileBytes);
                retJSON = js.Serialize(new { Result = objFileTransfer.TransferFile(filename, fileBytes) });
                Context.Response.Write(retJSON);
                // fileBytes now contains the content of the file
                // filename contains the name of the file
            }            
        }

Is this webservice get multipart form data?
When an iPhone developer consume this api they are not getting response.

private FtpWebRequest ftpRequest = null;
        //private FtpWebResponse ftpResponse = null;
        private Stream ftpStream = null;
        private int bufferSize = 2048;

        public string TransferFile(string filename, byte[] fileContent)
        {
            string strMsg = string.Empty;
            try
            {
                
                /* Create an FTP Request */
                String uploadUrl = String.Format("{0}/{1}/{2}", "ftp://Address", "DirectoryName", filename);
                ftpRequest = (FtpWebRequest)FtpWebRequest.Create(uploadUrl);
                /* Log in to the FTP Server with the User Name and Password Provided */
                ftpRequest.Credentials = new NetworkCredential("Username", "Password");
                /* When in doubt, use these options */
                ftpRequest.UseBinary = true;
                ftpRequest.UsePassive = true;
                ftpRequest.KeepAlive = true;
                /* Specify the Type of FTP Request */
                ftpRequest.Method = WebRequestMethods.Ftp.UploadFile;
                try
                {
                    
                    ftpRequest.ContentLength = fileContent.Length;

                    Stream requestStream = ftpRequest.GetRequestStream();
                    requestStream.Write(fileContent, 0, fileContent.Length);
                    requestStream.Close();
                    FtpWebResponse response = (FtpWebResponse)ftpRequest.GetResponse();
                    strMsg = "File Upload Status: " + response.ToString();
                    
                }
                catch (Exception ex) { Console.WriteLine(ex.ToString()); }
                /* Resource Cleanup */
                ftpStream.Close();
                ftpRequest = null;
            }
            catch (Exception ex) { Console.WriteLine(ex.ToString()); }
            return strMsg;
 
        }

解决方案

Hello Rajesh,

Following are sample code. When clicking on submit button it will post selected files data to the mentioned (action) website.

<form id="Form1" action="htt://mysite.com/photo" method="post" enctype="multipart/form-data">
     <input id="myPhoto" name="myPhoto" type="file" />
     <input type="submit" />
</form>

Thanks,
Imdadhusen

Please check the answer - WCF service to accept a post encoded multipart/form-data[^].

This might help you.

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