如何在for循环中获得0作为最后一个数字？ [英] how to get 0 as last number in for loop?

问题描述

嘿

我在c ++中打招呼，

我从下面链接写程序：

遇到麻烦寻找最大值，最小值（ARRAY）[^] [ ^ ]



这个工作正常但是我想改变程序如下：

例如当用户输入10个数字来获得min&最后一个数字应该是0.

我的意思是最后一个数字应该是0，如果它不是错误就出现了。

Hey
I ''m begginer in c++,
I write program from below link:
Having Trouble Finding Maximum, Minimum (A R R A Y)[^][^]

this works fine but I want to change the program as below:
for example when user enter 10 number to get min & max the last number should be 0.
I mean the last number should be 0 and if it''s not an error shows up.

推荐答案

问题是什么？只需检查 a [length-1] == 0 ，即

And what''s the problem? Just check if a[length-1] == 0, namely

if ( a[length-1] == 0)
{
  // OK
}
else
{
  // handle error
}

应该是相当容易。您只需使用 while 循环来完成arroy，当您找到零时，循环结束：

Hi,

that should be fairly easy. You just use a while loop to go through the arroy and when you find zero, the loop ends:

#include <stdlib.h>
#include <stdlio.h>
#include <limits.h>

// function that finds and prints the MIN and MAX array value
void FindMinAndMax(int* array, int length)
{
   int Min = INT_MAX; 
   int Max = INT_MIN;

   // here we check for the error
   if (array[length-1] != 0)
   {
      printf("Error: Array must end with 0 !!!");
      return ;
   }

   int i = 0;
   while (array[i] != 0)
   {
       if (array[i] > Max)
           Max = array[i]; 

       if (array[i] < Min)
           Min = array[i];   

       i++;     
   }
   
   printf("Min = %d\n", Min);
   printf("Max = %d\n", Max);
}

希望这会有所帮助。



祝你好运。

JK

Hope this helps.

Best regards.
J.K.

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