本地网络上的套接字通信 [英] Socket communication on local network
问题描述
我有一个家庭本地网络，有三台电脑A，B和C，还有一台路由器（一个ISP盒子）。计算机的特征如下：
-
A：
- Windows 10家庭版，连接Wi-Fi，IP地址：192.168.1.10
-
B：
- Windows 10家庭版，连接以太网，IP地址：192.168.1.14
-      
C：
- Windows 10专业版，连接Wi-Fi，IP地址：192.168.1.15
所有计算机在文件资源管理器中相互可见（路由器，地址192.168.1.1，也可见）。我可以在远程桌面中从A或B连接到C.因此
本地网络组件之间的连接完全可以运行。
现在，我有两个应用程序Client.exe和Server.exe，它们通过套接字在同一台计算机上进行通信，具有以下实现特性：
Client.exe：
-
C＃浏览器外的Silverlight应用程序
-
插座端口：4530
-
服务器IP地址："192.168.0.1"
-
实现System.Net.Sockets.Socket
Server.exe：
-
C＃应用
-
监听端口：4530
-
服务器IP地址："192.168.0.1"
-
侦听IP地址：System.Net.IPAddress.Any
-
implements：System.Net.Sockets.TcpListener
由于这在同一台计算机上运行良好的双向请求 - 响应，我想在上述家庭网络的两台计算机上运行它们。
因此，我在A上安装了客户端，在C上安装了服务器，在代码中相应地将服务器IP地址更改为C的（192.168.1.15）。我还在路由器上打开了端口
4530对于C计算机。
我在C上启动了Server.exe并从控制台执行'netstat -an'：端口4530被标记为'正在'。但是当我从C启动Client.exe时它无法建立
连接。
要做什么，以便在两台本地联网的计算机上运行我的套接字客户端 - 服务器应用程序？
谢谢
嗨Opariti，
根据根据你的描述，在我看来没有问题，我想也许客户端和服务器之间可能存在一些网络问题。我已经制作了一个简单的控制台应用程序，希望它对你有用。
服务器（10.157.13.69）。
static void Main（string [] args）
{
int port = 80;
string host =" 10.157.13.69";
IPAddress ip = IPAddress.Parse（host）;
IPEndPoint ipe = new IPEndPoint（ip ，port）;
Socket s = new Socket（AddressFamily.InterNetwork，SocketType.Stream，ProtocolType.Tcp）;
s.Bind（ipe）;
s.Listen（0）;
Console.WriteLine（"等待客户端"）;
套接字temp = s.Accept（）;
Console.WriteLine（" connected"）;
string recvStr ="" ;;
byte [] recvBytes = new byte [1024];
int bytes;
bytes = temp.Receive（recvBytes，recvBytes.Length，0）;
recvStr + = Encoding.ASCII.GetString（recvBytes，0，bytes）;
Console.WriteLine（" server get message：{0}"，recvStr）;
string sendStr =" ok！客户端发送消息成功！";
byte [] bs = Encoding.ASCII.GetBytes（sendStr）;
temp.Send（bs，bs.Length，0）;
temp.Close（）;
s.Close（）;
Console.ReadLine（）;
}客户（10.157.13.70）
static void Main（string [] args）
{
try
{
int port = 2000;
string host =" 10.157.13.69" ;;
IPAddress ip = IPAddress.Parse（host）;
IPEndPoint ipe = new IPEndPoint（ip，port）;
Socket c = new Socket（AddressFamily.InterNetwork，SocketType.Stream，ProtocolType.Tcp）; Console.WriteLine（QUOT; Conneting ..."）;
c.Connect（ipe）;
string sendStr =" hello！这是套接字测试";
byte [] bs = Encoding.ASCII.GetBytes（sendStr）; Console.WriteLine（"发送消息"）;
c.Send（bs，bs.Length，0）;
string recvStr ="" ;;
byte [] recvBytes = new byte [1024];
int bytes;
bytes = c.Receive（recvBytes，recvBytes.Length，0）; recvStr + = Encoding.ASCII.GetString（recvBytes，0，bytes）;
Console.WriteLine（" client get message：{0}"，recvStr）; c.Close（）;
}
catch（ArgumentNullException e）
{
Console.WriteLine（" argumentNullException：{0}"，e）;
}
catch（SocketException e）
{
Console.WriteLine（" SocketException：{0}"，e）;
}
Console.WriteLine（"按Enter键退出"）;
}结果。
最好的问候
Abraham
          
Hi,
I have a home local network, with three computers A, B, and C, plus a router (an ISP box). The characteristics of the computers are as following:
- A:
- Windows 10 Family Edition, connection Wi-Fi, IP address: 192.168.1.10
- B:
- Windows 10 Family Edition, connection Ethernet, IP address: 192.168.1.14
- C:
- Windows 10 Professional Edition, connection Wi-Fi, , IP address: 192.168.1.15
All computers are visible each other in File Explorer (router, address 192.168.1.1, is also visible). I can connect in Remote Desktop from A or B into C. Therefore the connection between the local network components is fully operational.
Now, I have two applications, Client.exe and Server.exe, that communicate in the same computer via sockets, with the following implementation characteristics:
Client.exe:
- C# out-of-browser Silverlight application
- socket port: 4530
- server IP address: "192.168.0.1"
- implements System.Net.Sockets.Socket
Server.exe:
- C# application
- listener port: 4530
- server IP address: "192.168.0.1"
- listen on IP address: System.Net.IPAddress.Any
- implements: System.Net.Sockets.TcpListener
As this works fine two-ways request-response in the same computer, I want to run them on two computers of the above home network.
Therefore, I installed Client on A and the Server on C, changing accordingly in the code the server IP address to the C’s one (192.168.1.15). I also opened the port 4530 on router for the C computer.
I started Server.exe on C and did ‘netstat –an’ from console: the port 4530 was marked as ‘listening’. But when I started Client.exe from C it couldn’t establish the connection.
What is to be done so that to make running my socket Client-Server application on the two locally networked computers?
Thanks
Hi Opariti,
According to your description, there is no problem it seems to me, I think maybe some network problems between the client and the server. I have made a simple console application, wish it is useful to you.
Server(10.157.13.69).
static void Main(string[] args) { int port = 80; string host = "10.157.13.69"; IPAddress ip = IPAddress.Parse(host); IPEndPoint ipe = new IPEndPoint(ip, port); Socket s = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); s.Bind(ipe); s.Listen(0); Console.WriteLine("wait for the client"); Socket temp = s.Accept(); Console.WriteLine("connected"); string recvStr = ""; byte[] recvBytes = new byte[1024]; int bytes; bytes = temp.Receive(recvBytes, recvBytes.Length, 0); recvStr += Encoding.ASCII.GetString(recvBytes, 0, bytes); Console.WriteLine("server get message:{0}", recvStr); string sendStr = "ok!Client send message successful!"; byte[] bs = Encoding.ASCII.GetBytes(sendStr); temp.Send(bs, bs.Length, 0); temp.Close(); s.Close(); Console.ReadLine(); }Client(10.157.13.70)
static void Main(string[] args) { try { int port = 2000; string host = "10.157.13.69"; IPAddress ip = IPAddress.Parse(host); IPEndPoint ipe = new IPEndPoint(ip, port); Socket c = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); Console.WriteLine("Conneting…"); c.Connect(ipe); string sendStr = "hello!This is a socket test"; byte[] bs = Encoding.ASCII.GetBytes(sendStr); Console.WriteLine("Send Message"); c.Send(bs, bs.Length, 0); string recvStr = ""; byte[] recvBytes = new byte[1024]; int bytes; bytes = c.Receive(recvBytes, recvBytes.Length, 0); recvStr += Encoding.ASCII.GetString(recvBytes, 0, bytes); Console.WriteLine("client get message:{0}", recvStr); c.Close(); } catch (ArgumentNullException e) { Console.WriteLine("argumentNullException: {0}", e); } catch (SocketException e) { Console.WriteLine("SocketException:{0}", e); } Console.WriteLine("Press Enter to Exit"); }Result.
Best Regards
Abraham
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