当两个具有相同值的项目时，如何从下拉列表中获取所选项目 [英] how to get selected item from drop down list when two items having same value

问题描述

我正从具有roomno的数据库中获取下拉列表绑定。作为textfield和guestid的值如：

roomno = 102，GuestID = 2;

romno = 103，guestid = 2;

roomno = 104，guestid = 1;



当我们将这些数据绑定到下拉列表并选择roomno：103时，它将始终选择具有相同值的第一个索引上的项目（如roomno 102和103都有相同的猜测，即2）



我如何选择具有相同值的下一个索引上的项目;

plz recommended我的任何解决方案....

i use！（回帖）在页面加载但它不起作用。



thanx提前！！！ ：）

i am having a drop down list bind from database having roomno. as textfield and guestid as value like :
roomno=102, GuestID=2;
romno=103, guestid=2;
roomno=104, guestid=1;

when we bind this data to drop down list and select roomno: 103 it will always select the item on first index with same value (as roomno 102 and 103 both having same guestid i.e. 2)

how do i select the item on next index having same value;
plz suggest me any solution for ds....
i use !(is post back) on pageload but it doesnt work for this.

thanx in advance!!! :)

推荐答案

大家好，请尝试这个，如果多个项目有保存值，您可以轻松获得所选项目的索引。

Hello you please try this and you can get easily index of selected item if more than one items have save values.

ddlRoomNo.SelectedIndex = ddlRoomNo.Items.IndexOf(ddlRoomNo.Items.FindByText("103"));

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