如何使用通配符替换字符串中的字符串 [英] How to replace charecters in a string with wildcard

问题描述

我想用一个？替换20120101。但是，我搜索的20120101字符串并不总是一样的。它始终以2开头，并且始终包含8个字符。它可能是20121225,20130510等。



我有以下代码，它对整数有效。

Hi,

I want to replace 20120101 with a ?. But, the 20120101 string I search for won''t always be the same. It will always start with a 2, and always contain 8 characters. It may be 20121225, 20130510, etc.

I have the following code and its working fine to integers.

string MyString ="SELECT Stuff FROM Table WHERE Code = Foo AND DATE=20120101";
                            string Fixed = Regex.Replace(MyString, @"DATE=2\d{7}", "DATE=?");

现在我想为字符串做同样的事情。

now i want to do the same for string.

string MyString ="SELECT Stuff FROM Table WHERE Code = Foo AND DATE=abcdefgh";
                            string Fixed = Regex.Replace(MyString, @"DATE=a\d{7}", "DATE=?");

此代码不替换文本。



请帮帮我

this code is not replacing the text.

please help me

推荐答案

那是因为''\d''是rexeg -speak for a digit：''0''''9''，因为你的字符串包含abcdefgh而且根本没有数字，所以它永远不会匹配。



尝试

That''s because ''\d'' is rexeg-speak for a digit: ''0'' to ''9'', Since your string contains "abcdefgh" and no digits at all, it will never match.

Try

@"DATE=.{7}"

任意角色中的七个，或者：

for seven of any character, or:

@"DATE=\w{7}"

七个alphnumerics，或：

for seven alphnumerics, or:

@"DATE=[a-zA-Z]{7}"

七个大写或小写字母。



获取<的副本a href =http://www.ultrapico.com/Expresso.htm> Expresso [ ^ ] - 它是免费的，它会检查并生成正则表达式。

for seven upper or lower case alphabetics.

Get a copy of Expresso [^] - it''s free, and it examines and generates Regular expressions.

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