如何通过名字在Android中得到一个类型数组的资源值? [英] How to get a value from a typed array resource by name in Android?

查看:416
本文介绍了如何通过名字在Android中得到一个类型数组的资源值?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

假设我有一个这样的资源的XML文件:

Suppose I have a resource xml file like this:

<?xml version="1.0" encoding="UTF-8"?>
<resources>
    <array name="difficulties">
        <item>
            <integer name="level">1</integer>
            <integer name="fixed_blocks">2</integer>
            <integer name="color_count">2</integer>
        </item>
        <item>
            <integer name="level">2</integer>
            <integer name="fixed_blocks">4</integer>
            <integer name="color_count">3</integer>
        </item>
        <item>
            <integer name="level">3</integer>
            <integer name="fixed_blocks">6</integer>
            <integer name="color_count">3</integer>
        </item>
    </array>    
</resources>

我如何从项目按名称获取整数值?在的TypedValue 的API似乎并没有包含此的任何方法。如果这是不可能与 TypedArray 是怎么回事?

How can I get the integer values from an item by name? The TypedValue's API doesn't seem to contain any methods for this. If this is not possible with the TypedArray how IS it?

如果我可以通过它的序号项目得到一个值马上就好了。

If I can get a value from an item by its ordinal it will be OK too.

推荐答案

我不记得这是可能的(但我可能是错的)。通过项目的结构(在困难阵列),你可以做其他的事情来看,你可以使用整数数组的数组。了解该项目阵列级别在第一的位置, fixed_blocks 作为第二个位置等,你可以很容易地获取值。这方面的例子,你可以在这里找到 Android的资源 - 阵列的阵列

I don't recall this being possible(but I could be wrong). Judging by the structure of an item(in the difficulties array) you could do something else, you could use an array of integer arrays. Knowing that the item array has level at the first position, fixed_blocks as the second position etc you could easily get the values. An example of this you can find here Android Resource - Array of Arrays

编辑:
这是你要寻找的方法是什么?

Is this the method you're looking for?

private int[] getLevelConstants(int level) {
    int[] result = null;
    TypedArray ta = getResources().obtainTypedArray(R.array.difficulties);
    // keep in mind the differences between the level(starts at 1) and the index of the difficulties array which starts at 0
    int id = ta.getResourceId(level, 0); 
    if (id > 0) {
        result = getResources().getIntArray(id);
    } else {
        // something bad
    }
    return result;
}

和数组将是:

<?xml version="1.0" encoding="utf-8"?>
<resources>

    <integer-array name="difficulties">
        <item>@array/level1</item>
        <item>@array/level2</item>
    </integer-array>

    <integer-array name="level1" >
        <item>1</item>
        <item>2</item>
        <item>2</item>
    </integer-array>

    <integer-array name="level2" >
        <item>2</item>
        <item>4</item>
        <item>3</item>
    </integer-array>

</resources>

这篇关于如何通过名字在Android中得到一个类型数组的资源值?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆