如何调用“公共”阵列？ [英] How do I call a 'public' array?

问题描述

如何定义一个包含数组的公共方法？



我想将方法​​设置为public，以便它可以与多个按钮一起使用方法，但程序说并非所有代码路径都返回值。我认为这意味着我没有将''void''值更改为正确的类型但是有人可以告诉我它是什么吗？



我有以下代码：

How do I define a public method that has an array in it?

I would like to set a method to public so it can be used with multiple button methods but the program says ''not all code paths return a value''. I assume that means I have not changed the ''void'' value to the correct type but can anyone tell me what it is?

I have the following code:

        public String bob ()
        {
        string [] averages = new string[2];
        averages[0] = value1.Text;
        averages[1] = value2.Text;

        }

        private void button1_Click(object sender, EventArgs e)
        {
            bob();
            label1.Text = averages[1];

}

谢谢。



已添加代码块[/编辑]

Thanks.

Code block added[/Edit]

推荐答案

更改 bob（）进入：

Hi,

Change bob() into this:

public String[] bob ()
       {
       string [] averages = new string[2];
       averages[0] = value1.Text;
       averages[1] = value2.Text;
       return averages;
       }

更多关于返回的关键字：

http://msdn.microsoft.com/en-us/library/1h3swy84.aspx [ ^ ]

希望这会有所帮助。

More about the return keyword:
http://msdn.microsoft.com/en-us/library/1h3swy84.aspx[^]
Hope this helps.

为什么不这样做呢相反，既然你似乎正在尝试做什么？

Why not just do this instead, since it''s what you appear to be trying to do?

private void button1_Click(object sender, EventArgs e)
{
   label1.Text = value2.Text;
}

public string[] bob ()
{
    string [] averages = new string[2];
    averages[0] = value1.Text;
    averages[1] = value2.Text;
    return averages;
}

private void button1_Click(object sender, EventArgs e)
{
    string[] bobResult = bob();
    label1.Text = bobResult[1];
}

这是您问题的一个解决方案。方法bob返回字符串数组。在button1_Click方法中，bob调用的结果被赋值给类型为string []且名为bobResult的变量。

This is one solution to your question. The method "bob" returns string array. In the button1_Click method the result from "bob" call is assigned to variable with type string[] and name bobResult.

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