正在运行的线程的时候是什么处理器吗？ [英] What does Handler do when running a thread?
问题描述
我真搞不清楚这一点，但是当我从我的SurfaceView trigging一个线程，发送即时消息处理程序，像这样的构造
I'm really confused about this, but when I'm trigging a thread from my SurfaceView, im sending a Handler with the constructor like this
private static Thread thread;
public SurfaceView(Context localContext) {
//other stuff
thread = new Thread(mySurfaceHolder, myEngine, this, new Handler());
//other stuff
}
在我的线程级的我分配一个处理程序，对象，我从我的观点发送的处理程序，如：
and in my thread-class I assign a Handler-object with the handler I sent from my view, like this:
public Thread (SurfaceHolder lHolder,
Engine lEngine,
View lView,
Handler lHandler){
surfaceHolder = lHolder;
engine = lEngine;
view = lView;
handler = lHandler;
}
那么，这是什么处理器吗？我从来没有在任何方面我的线程类使用它，为什么仍然显示出我，我应该送处理程序与构造Web上的例子吗？
我看不到连接...
So what does this Handler do? I never use it in my thread-class in any ways, so why are the examples on the web still showing me that I should send a handler with the constructor? I can't see the connection....
在此先感谢！
推荐答案
我假设你的code要扩展主题，因为没有构造采取的处理程序Thread类。处理程序是用来回传达给UI线程，因为Android的线程模型要求在一个特殊的专用线程执行的UI操作。
I assume in your code you are extending Thread, because there is no constructor taking a handler for the Thread class. The handler is used to communicate back to the UI thread, as the Android threading model requires UI operations to be performed on a special dedicated thread.
在创建一个新的线程，code在后台线程中执行，因此UI的操作是不安全的。如果你不需要做任何事情UI相关的，可以删除的处理程序。
When creating a new thread, the code is executed in a background thread, and thus UI-operations are unsafe. If you do not need to do anything UI-related, you can remove the handler.
由于Android API 3，有 AsyncTask的，这使得通信背景和UI之间容易并减轻需要使用的处理程序。
Since Android API 3, there is AsyncTask, which makes communication between background and UI easier and alleviates the need to use a handler.
例如：
- For an example of using a Handler, see this.
- See Painless Threading as well, which contains links to sample projects using threading.
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