Safari中不支持编码 [英] Coding not supported in Safari

问题描述

以下编码在IE中运行良好。我还需要在Safari中使用此代码。

The below coding works well in IE. I also need to work this code in safari.

function Transmit_SOAP()
{
if(window.ActiveXObject)
{//For IE Browsers. This coding works well in IE browsers
var tempNode=xmlSoapTemplate.selectSingleNode(pathString+"xmlDatasets");
tempNode.appendChild(xmlDataReturn.documentElement);
}

else
{//verify the code below.(Safari Support)
alert("Checking");
try{
var tempNode=xmlSoapTemplate.evaluate(pathString+"xmlDatasets", xmlSoapTemplate, null, XPathResult.ANY_TYPE,null);
}
catch (e)
{
alert(e);
}
tempNode.appendChild(xmlDataReturn.documentElement);
}
}

请核实旅行代码。显示警报后代码执行中断（正在检查）;



这是使用try catch时的错误

TypeError：未定义值（表达式xmlSoapTemplate.evaluate的结果）不是对象



下面的代码是xmlSoapTemplate

Kindly verify the safari code. The code execution breaks after showing the alert("Checking");

This is the error when using try catch
TypeError: Value undefined (result of expression xmlSoapTemplate.evaluate) is not object

The below code is xmlSoapTemplate

if(window.ActiveXObject)
{
//For IE Support.
//Begin by loading up the dataform via soap request
xmlSoapTemplate=new ActiveXObject("Microsoft.XMLDOM");
xmlSoapTemplate.onreadystatechange = function () {
if (xmlSoapTemplate.readyState == 4) Transmit_SOAP()
};
			
xmlSoapTemplate.load("../Dataforms/soap_1.xml");
}

// For Safari Support
 else
 {
 xmlSoapTemplate = new XMLHttpRequest();
 xmlSoapTemplate.open('GET','../Dataforms/soap_1.xml', true);
 xmlSoapTemplate.onreadystatechange = function() {
 if (xmlSoapTemplate.readyState == 4) {
  Transmit_SOAP()
   }
  }
  xmlSoapTemplate.send();
 }

推荐答案

void compatibility()
    {
        if (Request.UserAgent.IndexOf("AppleWebKit") > 0)
        {
            Request.Browser.Adapters.Clear();
        }
    }

将此代码粘贴到页面加载事件

paste this code on page load event

这篇关于Safari中不支持编码的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！