如何以编程方式创建弹出菜单 [英] How to create pop up menu programatically

问题描述

我是C＃语言的新手，我最近开始学习。我想通过编程创建弹出菜单。我正在使用Windows申请表。我可以使用工具箱中的contextmenustrip创建弹出菜单，但是如何在不使用工具箱绘图的情况下创建。我想通过编程来创建它。任何人都可以提供一些示例代码或示例。



提前致谢。

Hi,

I am new to C# language,I have started to learn recently. I want to create pop-up menu by programming. I am using windows application form. I am able to create pop up menu by using "contextmenustrip" from tool box, but how to create without drawing from toolbox. I want to create it by programming. Can any one provide me some sample code or examples.

Thanks in advance.

推荐答案

ContextMenuStrip cmp = new ContextMenuStrip（）;

cmp.Items.Add（From）;

cmp.Items.Add（To）;

cmp.Items.Add（重置）;

this.ContextMenuStrip = cmp;



我用上面的方法实现了这一点代码。

ContextMenuStrip cmp = new ContextMenuStrip();
cmp.Items.Add("From");
cmp.Items.Add("To");
cmp.Items.Add("Reset");
this.ContextMenuStrip = cmp;

I have achieved this by using above code.

使用MessageBox类''静态方法。显示（）

我已经证明了下面的过载。

Use the MessageBox class'' static method .Show()
I''ve demonstrated on of the over load below.

MessageBox.Show("Message","BoxTitle", MessageBoxButtons.OKCancel, MessageBoxIcon.Information);

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