从的Andr​​oid布局GridView的指标转化为行和列 [英] Android From gridview layout index convert into row and column

问题描述

如果我有指数从0开始在网格上的位置的，我怎么能把它转换成一排，列？我越来越有以下不正确的结果。幸运的是，我知道有多少行，我有列在我的情况下，其11 11.

  INT列=位置％列;INT排=位置/列;
 

解决方案

  // X：在区间[0水平位置;列-1]
// Y：在区间[0垂直位置;行-1]INT X =索引％列;
INT Y =指数/列;
INT列= X + 1;
INT排= Y + 1;
 

扭转：

  INT指数= X + Y *列;
 

或

  INT指数=（列 -  1）+（行 -  1）*列;
 

If I have index starting from 0, of a position on a grid, how can I turn that into a row, column? I'm getting incorrect results with the following. Fortunately I know how many rows and columns I have and in my case its 11 by 11.

int column = position % columns;

int row = position / columns;

解决方案

// x : horizontal position in range [0; columns-1]
// y : vertical position in range [0; rows-1]

int x = index % columns;
int y = index / columns;
int column = x + 1;
int row = y + 1;

to reverse:

int index = x + y * columns;

or

int index = (column - 1) + (row - 1) * columns;

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