如何使我的gridview的表列作为gridview中的超链接 [英] how can i make a table column of my gridview act as hyperlink in gridview

问题描述

我必须在gridview中显示我的表格数据 - 它们如



Job_No

加入日期，JOB TITLE，

因此当用户点击JOBTITLE栏中列出的作业中的特定作业

时，根据该作业的新页面将打开该特定作业

信息??????????????



请帮助..谢谢advace

i have to show my table data in gridview -- they are such as

Job_No
Joining Date, JOB TITLE ,
so when a user clicks on a particular job in the jobs listed in JOBTITLE column
,then a new page according to that job will open with that particular job
information ????????????????

Pls help ..thanks in advace

推荐答案

通过以下链接...

http://www.java2s.com/Tutorial/ASP.NET/0380__Data-Binding/AddingaHyperlinkFieldcontroltotheGridView.htm [ ^ ]

在ASP.NET中的GridView中创建HyperLinkField的实用指南 [ ^ ]

go through following links...
http://www.java2s.com/Tutorial/ASP.NET/0380__Data-Binding/AddingaHyperlinkFieldcontroltotheGridView.htm[^]
Practical Guide for Creating HyperLinkField in GridView in ASP.NET[^]

Quote：

<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="False"

        onrowcommand="GridView1_RowCommand">
        <Columns>
            <asp:BoundField DataField="id" HeaderText="id" />
            <asp:BoundField DataField="name" HeaderText="name" />
            <asp:TemplateField HeaderText="download">
            <ItemTemplate>
            <asp:LinkButton ID="lbtn" runat="server" Text="download" CommandName="downld" CommandArgument='<%#Eval("id") %>'></asp:LinkButton>
            </ItemTemplate>
            </asp:TemplateField>

        </Columns>
    </asp:GridView>

----------------- ----- -------------------------------------------------- -

-------------------------------------------------------------------------

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
   {
       if (e.CommandName == "downld")
       {
           string id = e.CommandArgument.ToString();

       }
   }

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