函数调用缺少参数列表 [英] Function call missing argument list

问题描述

我有4个班级：

点继承自Shape，Circle来自Point和Cylinder来自Circle。

point，circle，cylinder是Point，Circle，Cylinder的对象。

I have 4 classes:
Point inherits from Shape,Circle from Point and Cylinder from Circle.
point, circle, cylinder are objects to Point, Circle, Cylinder.

Shape *shapeVector[3];
shapeVector[0]=&point;
shapeVector[1] = &circle;
shapeVector[2] = &cylinder;

当我这样做时：

When I do this:

Shape *baseClassPtr=shapeVector[ 1 ];
baseClassPtr->GetName();

它正在工作。但是当我这样做时：

It is working.But when I do this:

virtualViaPointer( shapeVector[ i ] ); // for all i(0,1,2)

   void virtualViaPointer(  Shape *baseClassPtr )    
   {                         	   
	   cout << baseClassPtr->GetName() << ": " ; 
   }

我收到此错误：

I''m getting this error:

Error   2   error LNK1120: 1 unresolved externals 
Error	1	error LNK2019: unresolved external symbol "void __cdecl virtualViaPointer(class Shape const *)" (?virtualViaPointer@@YAXPBVShape@@@Z) referenced in function _wmain

推荐答案

除非我遗漏了某些内容，否则您只需要添加括号：

Unless I am missing something, it looks like you simply have to add the parenthesis:

cout << baseClassPtr->GetName() << ": " ;

你实际上没有显示GetName（）声明，但对我来说这看起来好像会解决它。



Soren Madsen

You did not actually show the GetName() declaration, but to me this looks like it would fix it.

Soren Madsen

这篇关于函数调用缺少参数列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！