值类型和引用类型整数之间的差异。 [英] Difference between value typeand reference type integer.

问题描述

我曾经认为引用类型不能包含valuetype .....请帮助。

question-

如果int a = 15是值类型。并且

int b = new int（）是引用类型。

那么为什么b = a被允许????





请帮助。

解决方案

  int  b =  new   int （）; 

不创建引用类型 - 它创建一个值类型。 int 始终是一个值类型， new int（）语法只允许完成，它不会创建任何堆上的新分配，并且不返回引用。

如果您查看IL，它会生成相同的代码：

  int  A =  new   int （） ; 
  int  B =  0 ; 

。locals init（[0] int32 A，
 [1] int32 B）
 IL_0000：nop 
 IL_0001：ldc.i4.0 
 IL_0002：stloc.0 
 IL_0003：ldc.i4.0 
 IL_0004：stloc.1 
 

int b = new int（）不是引用类型，它与说 int b = 0; 正好相同因为使用 new 运算符并不意味着您获得了引用类型。

话虽如此， int [] b = new int [10] 确实导致数组对象本身的引用类型，但每个成员仍然是价值类型。



有关更好的解释，请参阅 MSDN文档 [ ^ ]。

MSDN：值类型 [ ^ ]

Hi,

I used to think that reference type cannot contain valuetype.....Please help.
question-
if int a=15 is value type. and
int b=new int() is reference type.
Then why b=a is allowed????


Please help.

解决方案

int b=new int();

Does not create a reference type - it creates a value type. int is always a value type, the new int() syntax is just allowed for completion, it does not create any new allocation on the heap, and does not return a reference.
If you have a look at the IL it generates the same code:

int A = new int();
int B = 0;

.locals init ([0] int32 A,
              [1] int32 B)
IL_0000:  nop
IL_0001:  ldc.i4.0
IL_0002:  stloc.0
IL_0003:  ldc.i4.0
IL_0004:  stloc.1

int b = new int() is not a reference type, it is the same as saying int b = 0; Just because the new operator is used does not mean you are getting a reference type.
That being said, int[] b = new int[10] does result in a reference type on the array object itself, but each of the members are still value types.

For a better explanation, see MSDN Documentation here[^].
MSDN: Value Types[^]

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