Visual Basic随机数范围选择器 [英] Visual basic random number range selector
本文介绍了Visual Basic随机数范围选择器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想在我的项目中制作一个迷你游戏,你必须解决x的值,这是随机生成的,具体取决于用户选择的难度。虽然当我尝试这样做并通过说console.writeline(x)测试它时,它说
x由于它的保护级别而无法访问。
I am trying to make a mini game in my project were you have to solve the value of x which is randomly generated depending on the difficulty that the user chooses. Although when i try to do this and test it out by saying console.writeline(x) it says that x is inaccessible due to it's protection level.
If userinput = "a" Then
Dim x As Integer = Rnd.Next(1, 10)
ElseIf userinput = "b" Then
Dim x As Integer = Rnd.Next(1, 20)
ElseIf userinput = "c" Then
Dim x As Integer = Rnd.Next(1, 30)
End If
Console.Clear()
Console.WriteLine("Try and guess x.")
userinput = Console.ReadLine
Console.WriteLine(x)
有没有人知道如何解决这个问题?
Does anybody know how to fix this?
推荐答案
这是因为'范围'需要事先声明x。
It's because of 'scoping' where x needs to be declared before hand.
Module Module1
Sub Main()
Dim userinput As String = ""
Dim x As Integer
Dim Rnd As Random = New Random()
If userinput = "a" Then
x = Rnd.Next(1, 10)
ElseIf userinput = "b" Then
x = Rnd.Next(1, 20)
ElseIf userinput = "c" Then
x = Rnd.Next(1, 30)
End If
Console.Clear()
Console.WriteLine("Try and guess x.")
userinput = Console.ReadLine
Console.WriteLine(x)
End Sub
End Module
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