Android中随机图像？ [英] random image in Android?

问题描述

我试图与随机照片的图。我有code和没有错误，但是当我点击该按钮转到随机图像，它只是保持不变。

我的来源是：

 私有静态最终随机rgenerator =新的随机（）;私有静态最终整数[] = mImageIds
    {R.drawable.img2，R.drawable.img1，R.drawable.img3，};@覆盖
公共无效的onCreate（捆绑savedInstanceState）
{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;    整数q = mImageIds [rgenerator.nextInt（mImageIds.length）];
    ImageView的IV =（ImageView的）findViewById（R.id.imageviewyeah）;
    iv.setTag（Q）;    查看Next按钮= findViewById（R.id.next_image_button）;
    nextButton.setOnClickListener（本）;
}公共无效的onClick（视图v）
{
    开关（v.getId（））
    {
        案例R.id.next_image_button：
            意图I =新意图（这一点，RandomImage.class）;
            startActivity（ⅰ）;
            打破;
    }
}
 

解决方案

只要保持一个参考你的的ImageView 和呼叫 setImageResource（INT ID） 与随机的资源之一。你并不需要启动一个新的活动来检索随机资源ID ...

  @覆盖
公共无效的onCreate（捆绑savedInstanceState）
{
    super.onCreate（savedInstanceState）;
    的setContentView（R.layout.main）;    整数q = mImageIds [rgenerator.nextInt（mImageIds.length）];
    最后ImageView的IV =（ImageView的）findViewById（R.id.imageviewyeah）;    查看Next按钮= findViewById（R.id.next_image_button）;
    nextButton.setOnClickListener（新OnClickListener（）{
         公共无效的onClick（视图V）{
              INT资源= mImageIds [rgenerator.nextInt（mImageIds.length）];
              iv.setImageResource（资源）;
         }
    }）;
}
 

I am trying to make a view with random images. I have code and no errors but when I click the button to go to the random image it just stays the same.

My source is:

private static final Random rgenerator = new Random();

private static final Integer[] mImageIds = 
    { R.drawable.img2, R.drawable.img1, R.drawable.img3, };

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Integer q = mImageIds[rgenerator.nextInt(mImageIds.length)];
    ImageView iv = (ImageView) findViewById(R.id.imageviewyeah);
    iv.setTag(q);

    View nextButton = findViewById(R.id.next_image_button);
    nextButton.setOnClickListener(this);
}

public void onClick(View v)
{
    switch (v.getId())
    {
        case R.id.next_image_button:
            Intent i = new Intent(this, RandomImage.class);
            startActivity(i);
            break;
    }
}

解决方案

Just keep a reference to your ImageView and call setImageResource(int id) with one of the random resources. You don't need to start a new Activity to retrieve a random resource ID...

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Integer q = mImageIds[rgenerator.nextInt(mImageIds.length)];
    final ImageView iv = (ImageView) findViewById(R.id.imageviewyeah);

    View nextButton = findViewById(R.id.next_image_button);
    nextButton.setOnClickListener(new OnClickListener() {
         public void onClick(View V) {
              int resource = mImageIds[rgenerator.nextInt(mImageIds.length)];
              iv.setImageResource(resource);
         }
    });
}

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