二进制格式化程序错误 [英] Binary formatter error

问题描述

我试图从二进制文件中读取UINT32数字：

 尝试 
 {
 binaryStreem =  new  FileStream（filename，FileMode.Open，FileAccess.ReadWrite，FileShare.None）; 
 binaryStreem.Seek（ 0 ， 0 ）; 
 FPGATimer =（ UInt32 ）binformater.Deserialize（binaryStreem）; 
 TraceParameter =（ UInt32 ）binformater.Deserialize（binaryStreem）; 
 TraceLocation =（ UInt32 ）binformater.Deserialize（binaryStreem）; 
 binaryStreem.Close（）; 
} 
  catch （System.Exception ex）
 {
 MessageBox.Show（ex.Message）; 
} 

此行执行时出现异常：

 FPGATimer =（UInt32）binformater.Deserialize（binaryStreem）; 

例外是：

 {输入流不是有效的二进制格式。起始内容（以字节为单位）为：14-00-00-00-00-00-00-00-00-00-00-00-14 -00-00-00-00 ...} 

什么可能是探测器？



谢谢。

解决方案

你的文件不是用二进制格式编写的 - 所以你不能用它来读回来。 />
快速查看错误消息中显示的数据将表明它是原始二进制数据，可能是32位整数20,0,0,20

二进制格式化程序输出文件看起来更像是这样：

 0001000000FFFFFFFF01000000000000 
 0004010000000C53797374656D2E496E 
 74333201000000076D5F76616C756500 
 08140000000B0001000000FFFFFFFF01 
 00000000000 00004010000000C537973 
 74656D2E496E74333201000000076D5F 
 76616C75650008140000000B 

顺便提一下，这是两个整数值20和20 - 但二进制格式化程序将类名和相关信息添加到它。



您要么需要查看数据编写器，要么修改代码以读取原始数据 - 如果您知道内容应该是什么，那就是帮助

Im trying to read UINT32 numbers from binary file:

try
{
   binaryStreem = new FileStream(filename, FileMode.Open, FileAccess.ReadWrite, FileShare.None);
   binaryStreem.Seek(0, 0);
   FPGATimer = (UInt32)binformater.Deserialize(binaryStreem);
   TraceParameter = (UInt32)binformater.Deserialize(binaryStreem);
   TraceLocation = (UInt32)binformater.Deserialize(binaryStreem);
   binaryStreem.Close();
}
catch (System.Exception ex)
{
   MessageBox.Show(ex.Message);
}

I get an exception when this line executes:

FPGATimer = (UInt32)binformater.Deserialize(binaryStreem);

The exception is:

{"The input stream is not a valid binary format. The starting contents (in bytes) are: 14-00-00-00-00-00-00-00-00-00-00-00-14-00-00-00-00 ..."}

What might be the probem?

Thanks.

解决方案

Your file was not written with a BinaryFormatter - so you can''t read it back with one.
A quick look at the data shown in your error message would indicate that it is raw binary data, possibly the 32 bit integers 20, 0, 0, 20
A binary formatter output file looks more like this:

0001000000FFFFFFFF01000000000000
0004010000000C53797374656D2E496E
74333201000000076D5F76616C756500
08140000000B0001000000FFFFFFFF01
0000000000000004010000000C537973
74656D2E496E74333201000000076D5F
76616C75650008140000000B

That, by the way, is for the two integer values "20" and "20" - but the binary formatter adds the class names and related info to it.

You either need to look at the data writer, or modify your code to read raw data - if you know what the content is supposed to be, that would help.

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