如何在c Linux中创建4处理和管道消息？ [英] how can i create 4 Process and Piping a message in c Linux?

问题描述

我在C，Linux的开头...请问我怎样才能在c Linux中创建4处理和管道消息？



process1通过pipe1将结果发送到process2 ...进程2通过pipe2将结果发送到process3然后process3通过pipe3将结果提供给process4并且process4保存结果到文件..



等待你的回答...

非常感谢

-lida

Hi,

i m in the start of C, Linux ... may u help me please how can i create 4 Process and Piping a message in c Linux?

process1 give the result by pipe1 to process2 ... process 2 by pipe2 send the result to process3 then process3 give the result to process4 by pipe3 and process4 save the result into a file..

wait for ur kind answers...
many thanks
-lida

推荐答案

请参阅：

http ：//linux.die.net/man/2/pipe [ ^ ]，

http://forum.codecall.net/topic/60502-using-pipe-in​​-c-over-linux/#axzz2Ds7vJI7h [ ^ ]。

-SA

Please see:
http://linux.die.net/man/2/pipe[^],
http://forum.codecall.net/topic/60502-using-pipe-in-c-over-linux/#axzz2Ds7vJI7h[^].

—SA

请参阅以下链接

http://home.agh.edu.pl/~wojnicki/thesis/node52.html

仅用于3个进程： -

Its for only 3 processes :-

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/types.h>
#include <sys/wait.h>

#define MSGSIZE    14 
 
char *message = "hello, world!"; 
 
 
main() { 
char inbuf[MSGSIZE];
int p[3];

pid_t pid;
pid_t pid1;
 
if (pipe(p) == -1){ 
perror("pipe call"); 
exit(1); 
 
}


pid = fork();
pid1 = fork();


if(pid == -1){

perror("Fork failed");
exit(1);

}

if(pid | pid1 == 0)//process A
{
    close(p[0]); 
    write(p[1], message, MSGSIZE);
    read(p[1], message, MSGSIZE);
    write(p[2], message, MSGSIZE);
    
}

/*else if(pid1 == 0){

    close(p[1]);
    //read(p[1], message, MSGSIZE);
    write(p[2], message, MSGSIZE);
    
}*/


else{
    //parent process C
    close(p[2]); 
    read(p[0], inbuf, MSGSIZE);
    printf("Pipelined message return:%s\n", inbuf);
    wait(NULL); 
}

exit(0);
}

这篇关于如何在c Linux中创建4处理和管道消息？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！