如何删除按钮？ [英] How can I remove button?

问题描述

我有我的按钮的名称的字符串。说它是一个名为字符串A 。

I have a string with the name of my button. Say it is called String A.

String A = myButtonName;

现在，如果我想要做删除的按钮：

Now, if I want to remove the button by doing:

 layout.removeView(myButtonName);

本会的工作，但是，我不能做一个字符串。

This would work, but, I can't do that on a string.

我怎样才能做到这一点对我的字符串？

How can I do it on my string?

就是这样，现在我得到一个错误，因为它是一个字符串：

Like this, right now I am getting an error, since it is a string:

 layout.removeView(A);

我怎样才能删除视图与对应于景色的字符串？

How can I remove a view with a string which corresponds to a view?

从理论上讲，我想我的字符串类型强制转换为一个ViewGroup中

Theoretically, I want to typecast my string to a ViewGroup

简化问题：

我有一个字符串。该字符串的也的我的按钮的变量名。
我可以使用字符串删除的按钮？

I have a string. That string is also the variable name of my button. Can I remove the button using the string?

推荐答案

我知道了！所以，因为我只有一个字符串，我可以检查，看看是否该字符串等于对象：

I got it! So, because I have only a string, I can just check to see if that string equals the object:

if(myButtonName.equals("Blue")){

                    View myView = (View) findViewById(R.id.Blue);
                    ((ViewManager)v.getParent()).removeView(v);

                }

然后我可以手动删除对象本身。因为，如西所提到的，这是不可能删除与字符串对象的图。我检查它通过一个if语句，并更换对象之后，只是删除了看法。

Then I can manually remove the object itself. Because, as Sai mentioned, it is impossible to remove a view with a string object; I just removed the view after checking it through an if statement, and replacing the object.

您也可以使用开关：

  switch(hello) {
                case "Blue":

                    View myView = (View) findViewById(R.id.Blue);
                    ((ViewManager) v.getParent()).removeView(v);

                    break;

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