将XML reader.value值转换为整数 [英] Convert XML reader.value values to integer

问题描述

大家好！

我正在尝试比较XmlTextReader值以确定哪个值更大.

这是我到目前为止的代码:

Hi everyone!

I am trying to compare XmlTextReader values to determine which is greater in value.

This is the code I have so far:

int newVersion1 = 0;
            string xmlUrl1 = @"C:\Users\Programming\Desktop\update.xml";
            XmlTextReader reader1 = null;

            int newVersion2 = 0;
            string xmlUrl2 = @"C:\Users\Programming\Desktop\update2.xml";
            XmlTextReader reader2 = null;

            try
            {
                reader1 = new XmlTextReader(xmlUrl1);
                reader1.MoveToContent();
                string elementName = "";
                if ((reader1.NodeType == XmlNodeType.Element) && (reader1.Name == "sqldbfile"))
                {                    
                    while (reader1.Read())
                    {
                        if (reader1.NodeType == XmlNodeType.Element)
                        {                                                     
                            elementName = reader1.Name;
                        }
                        else
                        {                            
                            if (reader1.NodeType == XmlNodeType.Text)
                            {                                
                                switch (elementName)
                                {
                                    case "version":
                                        newVersion1 = Convert.ToInt32(reader1.Value);
                                        break;                                    
                                }
                            }
                        }
                    }
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
            finally
            {
                if (reader1 != null)
                {
                    reader1.Close();
                }
            }
            //////////////////////////////////////////////////////////////////////////////////////
            try
            {
                reader2 = new XmlTextReader(xmlUrl2);
                reader2.MoveToContent();
                string elementName = "";
                if (reader2.NodeType == XmlNodeType.Element)
                {
                    while (reader2.Read())
                    {
                        if ((reader2.NodeType == XmlNodeType.Element) && (reader2.Name == "sqldbfile"))
                        {
                            elementName = reader2.Name;
                        }
                        else
                        {
                            if (reader2.NodeType == XmlNodeType.Text)
                            {
                                switch (elementName)
                                {
                                    case "version":
                                        newVersion2 = Convert.ToInt32(reader2.Value);                                        
                                        break;
                                }
                            }
                        }
                    }
                }
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message);
            }
            finally
            {
                if (reader2 != null)
                {
                    reader2.Close();
                }
            }

            //string s1 = reader1.Value;
            //string s2 = reader2.Value;

            MessageBox.Show("reader 1 : " + reader1.Value);
            MessageBox.Show("reader 2 : " + reader2.Value);

当前输出:底部的消息框未显示reader1.value或reader2.value的任何输出.

预期输出:
XML文件在2个文件中的每个文件中都具有< version> 2.0.我想比较这两个以确定程序是否是最新的.我应该获取reader1.value和reader2.value的值.

我收到的错误是输入字符串的格式不正确！"有人知道我缺少什么吗?

Current Output: The MessageBoxes at the bottom are not presenting any output for reader1.value or reader2.value.

Intended Output:
The XML files have: <version>2.0 in each of the 2 files. I am wanting to compare these 2 to determine whether or not a program is up to date. I should be getting values for reader1.value and reader2.value.

The error I''m getting is "Input String is not in correct format!" Does anyone know what I''m missing?

推荐答案

转换?！ System.Xml.XmlReader.ReadElementContentAsInt或System.Xml.XmlReader.ReadContentAsInt有什么问题?无论如何，如果您需要转换"(正确的术语为解析")，则可以始终使用int.Parse或int.TryParse:
http://msdn.microsoft.com/en-us/library/system.xml. xmlreader.aspx [ ^ ]，
http://msdn.microsoft.com/en-us/library/system.int32. parse.aspx [ ^ ]，
http://msdn.microsoft.com/en-us/library/system.int32. tryparse.aspx [ ^ ].

此外，为什么要确定真正需要直接使用XML?您可以考虑序列化，而进行序列化的最佳方法是使用 Data Contract :
http://msdn.microsoft.com/en-us/library/ms733127.aspx [ ^ ].

另请参阅我过去的答案:
如何在我的表单应用程序? [ ^ ]，
创建属性文件... [

Convert?! What''s wrong with System.Xml.XmlReader.ReadElementContentAsInt or System.Xml.XmlReader.ReadContentAsInt? Anyway, if you need to "convert" (right term would be "parse"), you can always use int.Parse or int.TryParse:
http://msdn.microsoft.com/en-us/library/system.xml.xmlreader.aspx[^],
http://msdn.microsoft.com/en-us/library/system.int32.parse.aspx[^],
http://msdn.microsoft.com/en-us/library/system.int32.tryparse.aspx[^].

Besides, why are you so sure that your really need to work with XML directly? You could consider serialization, and the best approach to serialization would be using Data Contract:
http://msdn.microsoft.com/en-us/library/ms733127.aspx[^].

See also my past answers:
How can I utilize XML File streamwriter and reader in my form application?[^],
Creating property files...[^].

—SA

我没有阅读所有这些代码.但是，要将从XML获得的字符串转换为int，请使用int.TryParse.如果不是整数，则Convert.ToInt32会爆炸.

I am not reading all of this code. However, to convert the string you get from XML to an int, use int.TryParse. Convert.ToInt32 will blow up if it''s not an int.

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