HttpRequest.InputStream [英] HttpRequest.InputStream

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本文介绍了HttpRequest.InputStream的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

你好,

我正在尝试使用< g class ="gr_gr_82 gr-alert gr_gramm gr_inline_cards gr_run_anim Style multiReplace的.NET项目中的某些代码" data-gr-id ="82". id ="82" my ./g NET Core项目.在代码中是Request.InputStream Visual Studio说:"HttpRequest不包含'InputStream'的定义".我该如何解决?

I'm trying to use some code from a .NET project in <g class="gr_ gr_82 gr-alert gr_gramm gr_inline_cards gr_run_anim Style multiReplace" data-gr-id="82" id="82">my .</g>NET Core project. In the code the is a Request.InputStream that Visual Studio says: "HttpRequest does not contain a definition for 'InputStream'". How can I solve this?

代码如下:

推荐答案

您好,Daniel P aiva,

您是否使用继承ApiController的WebApi控件.

Do you use WebApi Control, which inherit ApiController.

ApiController中,RequestSystem.Net.Http.HttpRequestMessage.在 ControllerRequestSystem.Web.HttpRequestBase.

In ApiController, Request is System.Net.Http.HttpRequestMessage. In Controller, Request is System.Web.HttpRequestBase.

ApiController Request does not have a property named InputStream中,如果要检索WebApi中的内容.请尝试以下代码.

In ApiController Request does not have a property named InputStream, If you want to retrieve the content in WebApi. please try the following code.

 var stream = HttpContext.Current.Request.InputStream;

最诚挚的问候,

吴可乐


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