HttpRequest.InputStream [英] HttpRequest.InputStream
问题描述
你好,
我正在尝试使用< g class ="gr_gr_82 gr-alert gr_gramm gr_inline_cards gr_run_anim Style multiReplace的.NET项目中的某些代码" data-gr-id ="82". id ="82" my ./g NET Core项目.在代码中是Request.InputStream Visual Studio说:"HttpRequest不包含'InputStream'的定义".我该如何解决?
I'm trying to use some code from a .NET project in <g class="gr_ gr_82 gr-alert gr_gramm gr_inline_cards gr_run_anim Style multiReplace" data-gr-id="82" id="82">my .</g>NET Core project. In the code the is a Request.InputStream that Visual Studio says: "HttpRequest does not contain a definition for 'InputStream'". How can I solve this?
代码如下:
推荐答案
您好,Daniel P aiva,
您是否使用继承ApiController的WebApi控件.
Do you use WebApi Control, which inherit ApiController.
在ApiController
中,Request
是System.Net.Http.HttpRequestMessage
.在
Controller
,Request
是System.Web.HttpRequestBase
.
In ApiController
, Request
is System.Net.Http.HttpRequestMessage
. In
Controller
, Request
is System.Web.HttpRequestBase
.
在ApiController Request does not have a property named
InputStream中,如果要检索WebApi中的内容.请尝试以下代码.
In ApiController Request does not have a property named
InputStream, If you want to retrieve the content in WebApi. please try the following code.
var stream = HttpContext.Current.Request.InputStream;
最诚挚的问候,
吴可乐
这篇关于HttpRequest.InputStream的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!