将double []转换为IntPtr，然后转换为字节数组 [英] Converting double[] To IntPtr and then to Byte Array

问题描述

我需要将double数组转换为IntPtr，并将此IntPtr转换为字节数组.
我要进行反转也只是确认存储在字节数组中的值是正确的int数组.
我要执行的步骤是
 
double [] dmanagedArray = new double [length];
for(int intI = 0; intI< dmanagedArray.Length; intI ++)
{
dmanagedArray [intI] = intI * 10;
}
int大小= Marshal.SizeOf(dmanagedArray [0])* dmanagedArray.Length;
IntPtr srcPtr1 = Marshal.AllocHGlobal(size);
//这会将双精度数组复制到IntPtr. 元帅.Copy(dmanagedArray，0，srcPtr1，dmanagedArray.Length);
 
//现在让我们将此IntPtr转换为字节数组
byte [] byteArray =新的byte [dmanagedArray.Length] 
//Marshal.Copy(srcPtr1，byteArray，0，byteArray.Length);
 
在我的情况下，字节[]现在包含所有值为0的值.
我认为这是错误的.如何进行正确的转换.

Hi,
I have requirement to convert double array to IntPtr and this IntPtr to byte array.
I want to do the reversal also just confirm values stored in byte array is of correct int array.
The steps I am following is
 
double[] dmanagedArray = new double[length];
for (int intI = 0; intI < dmanagedArray.Length; intI++)
{
dmanagedArray[intI] = intI * 10;
}
int size = Marshal.SizeOf(dmanagedArray[0]) * dmanagedArray.Length;
IntPtr srcPtr1 = Marshal.AllocHGlobal(size);
// This will copy double array to IntPtr. 
Marshal.Copy(dmanagedArray, 0, srcPtr1, dmanagedArray.Length);
 
// Now let's convert this IntPtr to byte array
byte[] byteArray = new byte[dmanagedArray.Length] 
//Marshal.Copy(srcPtr1, byteArray, 0, byteArray.Length);
 
In my case what is happening is , byte[] now contains all the values as 0.
which I think is wrong. How to do right conversion. 

推荐答案

您需要启用不安全的操作才能使用指针算术.

You need to enable unsafe operation to use pointer arithmetic.

顺便说一句，为什么要使用double?如果需要64位整数，请使用 long ；如果需要32位整数，请使用 int (或者更好的是， ulong 和 uint ).使用浮点格式进行指针运算时，由于使用了指数"运算法则，可能会产生意想不到的结果.部分.

Btw, why use double? If you need 64-bit integer you use long, if you need 32-bit integer you use int (or better yet, ulong and uint). Use floating point format for pointer operations using pointer arithmetic can yield unexpected result because of the "exponent" part.

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