即使返回json也可以不支持jsonp吗? [英] Can jsonp be not supported even if json is being returned ?

问题描述

Guys i am trying to hit this webservice which returns me a json response

{"message":"ok","client_transaction_id":"2","transaction_token":"e52126c2b0570335ab33ce3a233c18aea90c7987","status":"1","img":"http://www.zipdial.com/zip2auth/images/access/e52126c2b0570335ab33ce3a233c18aea90c7987"}

Now obviously i need it in a variable and need to make a cross domain call using jsonp but i get an  "Uncaught SyntaxError: Unexpected token : " in chrome and "invalid label" in firefox .
Following are the calls that i have tried 
a)   <pre lang="Javascript"> $.ajax({
      type: ''GET'',
      url: Url,
      contentType: "application/json",
      crossDomain: true,
      data: {"customerToken": "31f65a57b1d6106c067bc00a51f9128f4db95d1d",   "clientTransactionId": "2", "callerid": "9968280904", duration: "180", "countryCode": "91", "z2vToken": "884acdd6f4293432e922d1d4b4566a3c9f1203c1"},
            dataType: ''jsonp'',
            success: function() { console.log(''Success!''); },
			error: function() { console.log(''Uh Oh!''); },
			jsonp: ''jsonp''
        });

我得到了哦作为答案
b)

 jQuery.getJSON(urlFromApi + "  ，功能(数据){
    警报(数据);
}); 

上面使用yahoo的开放式api进行的调用使它像一个魅力一样工作，但是当与网络服务一起使用时，我实际上需要使用的调用给了我与上面相同的错误.
因此，webservice(我没有使用过的第三方api)可能不支持jsonp吗? 输入:"GET"， 网址:网址， contentType:"application/json"， crossDomain:是的， 数据:{"customerToken":"31f65a57b1d6106c067bc00a51f9128f4db95d1d"，"clientTransactionId":"2"，"callerid":"9968280904"，持续时间:"180"，"countryCode":"91"，"z2vToken":"884acdd6f4293432d2c dataType:``jsonp''， 成功:function(){console.log(''Success！''); }， 错误:function(){console.log(``哦哦！''); }， jsonp:``jsonp'' });

我得到了哦作为答案
b)

 jQuery.getJSON(urlFromApi + "  ，函数(数据){
    警报(数据);
}); 

上面与yahoo的开放api一起使用的调用使它像一个魅力一样工作，但是当与Web服务一起使用时，我实际上需要使用的调用给了我与上面相同的错误.
因此，webservice(我没有使用过的第三方api)可能不支持jsonp吗?

Guys i am trying to hit this webservice which returns me a json response

{"message":"ok","client_transaction_id":"2","transaction_token":"e52126c2b0570335ab33ce3a233c18aea90c7987","status":"1","img":"http://www.zipdial.com/zip2auth/images/access/e52126c2b0570335ab33ce3a233c18aea90c7987"}

Now obviously i need it in a variable and need to make a cross domain call using jsonp but i get an  "Uncaught SyntaxError: Unexpected token : " in chrome and "invalid label" in firefox .
Following are the calls that i have tried 
a)   <pre lang="Javascript"> $.ajax({
      type: ''GET'',
      url: Url,
      contentType: "application/json",
      crossDomain: true,
      data: {"customerToken": "31f65a57b1d6106c067bc00a51f9128f4db95d1d",   "clientTransactionId": "2", "callerid": "9968280904", duration: "180", "countryCode": "91", "z2vToken": "884acdd6f4293432e922d1d4b4566a3c9f1203c1"},
            dataType: ''jsonp'',
            success: function() { console.log(''Success!''); },
			error: function() { console.log(''Uh Oh!''); },
			jsonp: ''jsonp''
        });

i get uh oh as the answer
b)

jQuery.getJSON(urlFromApi+"&callback=?",function(data) {
    alert(data);
});

The call used above with yahoo''s open apis makes it work like a charm but when used with the webservice i actually need to use gives me the same error as above.
So is possible that webservice(third party api on which i have no use) dos not support jsonp ?

解决方案

.ajax({ type: ''GET'', url: Url, contentType: "application/json", crossDomain: true, data: {"customerToken": "31f65a57b1d6106c067bc00a51f9128f4db95d1d", "clientTransactionId": "2", "callerid": "9968280904", duration: "180", "countryCode": "91", "z2vToken": "884acdd6f4293432e922d1d4b4566a3c9f1203c1"}, dataType: ''jsonp'', success: function() { console.log(''Success!''); }, error: function() { console.log(''Uh Oh!''); }, jsonp: ''jsonp'' });

i get uh oh as the answer
b)

jQuery.getJSON(urlFromApi+"&callback=?",function(data) {
    alert(data);
});

The call used above with yahoo''s open apis makes it work like a charm but when used with the webservice i actually need to use gives me the same error as above.
So is possible that webservice(third party api on which i have no use) dos not support jsonp ?

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