第二次出现特定字符后从字符串中获取子字符串 [英] getting a substring from a string after the 2nd occurrence of a particular character

问题描述

你好朋友，我想从第二次出现某个特定字符后，从字符串中获取一个子字符串.
例如
我有这样的琴弦
sw-100-133
sw-100-300
sw-100-200
sw-1000-200
sw-10-200
现在我想获得仅具有"sw-100"或完全由"sw-100"开头的字符串(不像sw-1000).我怎么得到它.
在此先感谢朋友

hello friends ,i want to get a substring from a string after the 2nd occurrence of a particular character.
for example
i have strings like this
sw-100-133
sw-100-300
sw-100-200
sw-1000-200
sw-10-200
now i want to get strings only having ''sw-100'' or by starting by ''sw-100'' exactly (not like sw-1000). how can i get it .
thanks in advance friends

推荐答案

尝试:

string s = "sw-100-133";
if (s.StartsWith("sw-100-"))
   {
   ...
   }

或者，您可以使用正则表达式:

Or, you could use a regex:

Regex myRegex = new Regex(@"sw\-\d\d\d[^\d].*");
if (myRegex.IsMatch((s))
   {
   ...
   }

第二种解决方案更灵活，但可能难以维护.

The second solution is more flexible, but may be harder to maintain.

试试这个:

Hi,
Try this:

string input = "sw-100-133";
Match match1 = Regex.Match(input, @"sw-100-.*", RegexOptions.IgnoreCase);
if (match1.Success)
Console.WriteLine(match1.Value);

谢谢

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