如何在HTML中打开弹出窗口 [英] How to open pop up in html

问题描述

我有一个html页面，我想在任何图像该页面上有图像的人"上拖动鼠标时，我希望这些图像以弹出样式打开并且图像大小为500,500;

i have a html page and i want when i drag mouse on any image ''the one who image available on my page'' then i want those image open on popup style and image size is 500,500;

推荐答案

您不能直接在HTML中执行此操作，因此需要javascript左右.

看看这些链接:
http://www.htmlcodetutorial.com/linking/linking_famsupp_70.html [ http://snipplr.com/view/3624/ [

You can''t do that directly in HTML, you''ll need javascript or so.

Take a look at these links:
http://www.htmlcodetutorial.com/linking/linking_famsupp_70.html[^]
http://snipplr.com/view/3624/[^]

Good luck!

HTML弹出窗口示例代码 [ ^ ]
弹出窗口 [ ^ ]

..and more

Example HTML Popup Window Code[^]
Popup Windows[^]

..and more here[^]

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